imageopenpolygon

(PHP 7 >= 7.2.0)

imageopenpolygonDraws an open polygon

Opis

imageopenpolygon ( resource $image , array $points , int $num_points , int $color ) : bool

imageopenpolygon() draws an open polygon on the given image. Contrary to imagepolygon(), no line is drawn between the last and the first point.

Parametry

obraz

Zasób obrazu, zwrócony przez jedną z funkcji tworzących obrazy, taką jak imagecreatetruecolor().

points

An array containing the polygon's vertices, e.g.:

points[0] = x0
points[1] = y0
points[2] = x1
points[3] = y1

num_points

Total number of points (vertices), which must be at least 3.

color

A color identifier created with imagecolorallocate().

Zwracane wartości

Zwraca TRUE w przypadku powodzenia, FALSE w przypadku błędu.

Przykłady

Przykład #1 imageopenpolygon() example

<?php
// Create a blank image
$image imagecreatetruecolor(400300);

// Allocate a color for the polygon
$col_poly imagecolorallocate($image255255255);

// Draw the polygon
imageopenpolygon($image, array(
        
0,   0,
        
100200,
        
300200
    
),
    
3,
    
$col_poly);

// Output the picture to the browser
header('Content-type: image/png');

imagepng($image);
imagedestroy($image);
?>

Powyższy przykład wyświetli coś podobnego do:

Output of example : imageopenpolygon()

Zobacz też:

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User Contributed Notes 1 note

up
-1
marco at oostende dot nl
1 year ago
In case you want to use an open polygon but are stuck with a PHP version prior to 7.2, a solution may be to 'backplot' your array to its original start. Say you have an array of pixels (below seperated by commas)

<?php
$arr
= array();
for (
$i = 0; $i < count($pixels); $i++) {
   
$pixel = explode(',', $pixels[$i]);
    if ((
$pixel[0] > 0) && ($pixel[1] > 0)) {
       
$arr[] = $pixel[0];
       
$arr[] = $pixel[1];
    }
}
imagepolygon($im, $arr, (count($arr) / 2), $otcolor);
?>

you can replace this by something like

<?php
$arr
= array();
for (
$i = 0; $i < count($pixels); $i++) {
   
$pixel = explode(',', $pixels[$i]);
   
$arr[] = $pixel[0];
   
$arr[] = $pixel[1];
}
// imageopenpolygon($im, $arr, (count($arr) / 2), $otcolor) is not possible, so...
for ($i = (count($pixels)-1); $i >= 0; $i--) {
   
$pixel = explode(',', $pixels[$i]);
   
$arr[] = $pixel[0];
   
$arr[] = $pixel[1];
}
imagepolygon($im, $arr, (count($arr) / 2), $otcolor);
?>
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