Please note that the information on warning count cannot be taken from the mysql_info() due to mysql bugs #41283 and #41285:
http://bugs.mysql.com/?id=41283
http://bugs.mysql.com/?id=41285
mysql_info
(PHP 4 >= 4.3.0, PHP 5)
mysql_info — Pobiera informacje o ostatnim zapytaniu
Opis
mysql_info
([ resource
$
identyfikator_połączenia
] ) : string
mysql_info() zwraca szczegółowe informacje o ostatnim
zapytaniu wykonanym przy użyciu podanego identyfikatora_połączenia.
Jeśli identyfikator_połączenia nie zostanie podany,
domyślnie przyjmowane jest ostatnio otwarte połączenie.
mysql_info() zwraca wartość typu string
dla poleceń wymienionych poniżej. Dla wszystkich innych zwracana jest
wartość FALSE. Format zwracanej wartości zależy od polecenia.
Przykład #1 Formaty zwracanych wartości
INSERT INTO ... SELECT ... String format: Records: 23 Duplicates: 0 Warnings: 0 INSERT INTO ... VALUES (...),(...),(...)... String format: Records: 37 Duplicates: 0 Warnings: 0 LOAD DATA INFILE ... String format: Records: 42 Deleted: 0 Skipped: 0 Warnings: 0 ALTER TABLE String format: Records: 60 Duplicates: 0 Warnings: 0 UPDATE String format: Rows matched: 65 Changed: 65 Warnings: 0
Informacja:
Dla poleceń typu INSERT ... VALUES, mysql_info() zwraca wartość różną od
FALSE, tylko jeśli w zapytaniu podanych zostało kilka wartości.
Patrz także: mysql_affected_rows()
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User Contributed Notes 5 notes
tomas at matfyz dot cz ¶
15 years ago
info at granville dot nl ¶
18 years ago
Imade a quick conversion of eric's function just to count matched or affected rows from a query.
/**GD gdf_db_count_query_v1: returns the amount of rows matched or affected by the last query. Must be used immediately after the concerned query.
*/
function gdf_db_count_query($link = 'dbh') {
$info_str = mysql_info($$link);
if (ereg("Records: ([0-9]*)", $info_str, $count) == false) {
ereg("Rows matched: ([0-9]*)", $info_str, $count);
}
return $count;
}
eric at projectsatellite dot com ¶
20 years ago
I agree that this is a useful function to use when trying to check on whether an update query matched a particular row. I created a simple function that returns an associative array with the values delineated in the returned string.
function get_mysql_info($linkid = null){
$linkid? $strInfo = mysql_info($linkid) : $strInfo = mysql_info();
$return = array();
ereg("Records: ([0-9]*)", $strInfo, $records);
ereg("Duplicates: ([0-9]*)", $strInfo, $dupes);
ereg("Warnings: ([0-9]*)", $strInfo, $warnings);
ereg("Deleted: ([0-9]*)", $strInfo, $deleted);
ereg("Skipped: ([0-9]*)", $strInfo, $skipped);
ereg("Rows matched: ([0-9]*)", $strInfo, $rows_matched);
ereg("Changed: ([0-9]*)", $strInfo, $changed);
$return['records'] = $records[1];
$return['duplicates'] = $dupes[1];
$return['warnings'] = $warnings[1];
$return['deleted'] = $deleted[1];
$return['skipped'] = $skipped[1];
$return['rows_matched'] = $rows_matched[1];
$return['changed'] = $changed[1];
return $return;
}
After trying to update a row that may or may not exist, you can use the above function like so:
$vals = get_mysql_info($linkid);
if($vals['rows_matched'] == 0){
mysql_query("INSERT INTO table values('val1','val2', 'valetc')", $linkid);
}
bdobrica at gmail dot com ¶
18 years ago
As a solution to the problem pointed in the post reffering to mysql_affected_rows() returning 0 when you are making an update query and the fields are not modified although the query is valid, i'm posting the following function. It is very simple and based on a previous post.
function mysql_modified_rows () {
$info_str = mysql_info();
$a_rows = mysql_affected_rows();
ereg("Rows matched: ([0-9]*)", $info_str, $r_matched);
return ($a_rows < 1)?($r_matched[1]?$r_matched[1]:0):$a_rows;
}
Hope you'll find it usefull.
carl at NOSPAMthep dot lu dot se ¶
21 years ago
This function can be used as a workaround for a misfeature of MySQL: on an UPDATE, rows that aren't updated _solely because they looked the same before_ will not be seen in mysql_affected_rows(). This causes problems when you want to use the result of the update to determine if there's need to do an INSERT. With MySQL you can do an INSERT IGNORE if there's no risk of if failing because of a duplicate key other than the one used in the UPDATE. However, if this isn't the case or you want a bit of RDBMS independence, there's no easy/pretty workaround. I think I'll resort to doing a SELECT to determine the primary key before doing the update/insert, as using the CVS version of PHP isn't an option for me.
