date_parse

(PHP 5 >= 5.2.0, PHP 7)

date_parseReturns associative array with detailed info about given date/time

Descrierea

date_parse ( string $datetime ) : array

Parametri

datetime

Date/time in format accepted by DateTimeImmutable::__construct().

Valorile întoarse

Returns array with information about the parsed date/time on success sau false în cazul eșecului.

Erori/Excepții

In case the date/time format has an error, the element 'errors' will contains the error messages.

Istoricul schimbărilor

Versiune Descriere
7.2.0 The zone element of the returned array represents seconds instead of minutes now, and its sign is inverted. For instance -120 is now 7200.

Exemple

Example #1 A date_parse() example

<?php
print_r
(date_parse("2006-12-12 10:00:00.5"));
?>

Exemplul de mai sus va afișa:

Array
(
    [year] => 2006
    [month] => 12
    [day] => 12
    [hour] => 10
    [minute] => 0
    [second] => 0
    [fraction] => 0.5
    [warning_count] => 0
    [warnings] => Array()
    [error_count] => 0
    [errors] => Array()
    [is_localtime] => 
)

Relative formats do not influence the values parsed from absolute formats, but are parsed into the "relative" element.

Example #2 date_parse() with relative formats

<?php
print_r
(date_parse("2006-12-12 10:00:00.5 +1 week +1 hour"));
?>

Exemplul de mai sus va afișa:

Array
(
    [year] => 2006
    [month] => 12
    [day] => 12
    [hour] => 10
    [minute] => 0
    [second] => 0
    [fraction] => 0.5
    [warning_count] => 0
    [warnings] => Array
        (
        )

    [error_count] => 0
    [errors] => Array
        (
        )

    [is_localtime] =>
    [relative] => Array
        (
            [year] => 0
            [month] => 0
            [day] => 7
            [hour] => 1
            [minute] => 0
            [second] => 0
        )

)

A se vedea și

add a note add a note

User Contributed Notes 11 notes

up
14
admin at torntech dot com
13 years ago
A warning to others. Some keys will return with a default value where others will return as false if the date string has it omitted. Unsure if this is a bug or feature, but hopefully this will save someone some time.
<?php
///Example
$input = "Feb 2010";
$info = date_parse($input);
var_dump($info);

/*Returns:
array(12) {
    ["year"]=> int(2010)
    ["month"]=> int(2)
    ["day"]=> int(1)    //<---expected false like below
    ["hour"]=> bool(false)
    ["minute"]=> bool(false)
    ["second"]=> bool(false)
    ["fraction"]=> bool(false)
    ["warning_count"]=> int(0)
    ["warnings"]=> array(0) { }
    ["error_count"]=> int(0)
    ["errors"]=> array(0) { }
    ["is_localtime"]=> bool(false)
}*/
?>
up
8
alvaro at demogracia dot com
13 years ago
Be aware that date_parse() is happy with just a time zone and it can be pretty counter-intuitive. E.g.:

<?php
var_dump
( date_parse('Europe/Madrid') );
?>

... prints an array where year, month, day... are FALSE. But so do these:

<?php
var_dump
( date_parse('A') );
var_dump( date_parse('B') );
var_dump( date_parse('X') );
?>

Don't forget to further validate date_parse()'s output even when it isn't FALSE and the 'errors' key is empty.
up
2
paul at juniperwebcraft dot com
6 years ago
It's sometimes useful to be able to store incomplete dates, for example when all you know of someone's birthdate is the year or the month and day.

date_parse() handles (and MySQL accepts) dates containing zero-value elements such as "2017-00-00" and "0000-03-29", leaving it up to the parent application to determine when to require and how to handle missing date elements. date_parse() correctly reports zero values for zero-value date elements, reports an 'invalid date' warning, and does not report an error.

Example 1: Year only
<?php print_r( date_parse( '2017-00-00' ) );?>
generates:
<?php
Array
(
    [
year] => 2017
   
[month] => 0
   
[day] => 0
   
[hour] =>
    [
minute] =>
    [
second] =>
    [
fraction] =>
    [
warning_count] => 1
   
[warnings] => Array
        (
            [
11] => The parsed date was invalid
       
)

    [
error_count] => 0
   
[errors] => Array
        (
        )

    [
is_localtime] =>
)
?>

Example 2: Month and day only
<?php print_r( date_parse( '0000-03-29' ) )?>
generates:
<?php
Array
(
    [
year] => 0
   
[month] => 3
   
[day] => 29
   
[hour] =>
    [
minute] =>
    [
second] =>
    [
fraction] =>
    [
warning_count] => 1
   
[warnings] => Array
        (
            [
11] => The parsed date was invalid
       
)

    [
error_count] => 0
   
[errors] => Array
        (
        )

    [
is_localtime] =>
)
?>

However, simply omitting date elements gives PHP too much discretion in second-guessing our intentions:

Example 3: Truncated date:
<?php print_r( date_parse( '2017-03' ) )?>
generates:
<?php
Array
(
    [
year] => 2017
   
[month] => 3
   
[day] => 1
   
[hour] =>
    [
minute] =>
    [
second] =>
    [
fraction] =>
    [
warning_count] => 0
   
[warnings] => Array
        (
        )

    [
error_count] => 0
   
[errors] => Array
        (
        )

    [
is_localtime] =>
)
?>
In this case, PHP supplies a day value of 1 and does not report a warning.

Similarly, this feature of accepting zero date elements does not carry over to timestamps:

<?php $dDate = strtotime( '2017-03-00' );
print_r( getdate( $dDate ) ); ?>

displays:

<?php Array
(
    [
seconds] => 0
   
[minutes] => 0
   
[hours] => 0
   
[mday] => 28
   
[wday] => 2
   
[mon] => 2
   
[year] => 2017
   
[yday] => 58
   
[weekday] => Tuesday
   
[month] => February
   
[0] => 1488268800
)
?>
In this case, PHP interprets the "zeroth" day of March to be the last day of February.
up
1
edg at greenberg dot org
5 years ago
Passing "YYYY-MM" results in a valid date. Be careful to validate that your submitted date passed YOUR requirements.
up
0
y dot adounis at gmail dot com
4 years ago
Developers, be aware that using "now" will return an empty array, ex :

<?php
date_parse
("now");
?>

Will return :

Array
(
    [year] =>
    [month] =>
    [day] =>
    [hour] =>
    [minute] =>
    [second] =>
    [fraction] =>
    [warning_count] => 0
    [warnings] => Array
        (
        )

    [error_count] => 0
    [errors] => Array
        (
        )

    [is_localtime] =>
)
up
0
ryan_a_martin at yahoo dot com
13 years ago
See checkdate() at http://php.net/manual/en/function.checkdate.php for Gregorian date validation.
up
0
gpayne at galenaparkisd com
16 years ago
Careful - date_parse is perfectly happy with something like this:

date_parse("2006-2-31");
up
-2
adamm at extratech dot com
11 years ago
A warning to some
<?php
$time
= "00:14:38"
$parse_date = date_parse($time);
echo
var_dump($parse_date) ."<br>";
//here you will get what you expect

$time = "-00:14:38"
$parse_date = date_parse($time);
echo
var_dump($parse_date) ."<br>";
//here you will recieve hours minutes and seconds as booleans and as false and you will get error set to "Unexpected character"

$time = "00:-14:38"
$parse_date = date_parse($time);
echo
var_dump($parse_date) ."<br>";
//here you will recieve the same as the above

$time = "00:14:-38"
$parse_date = date_parse($time);
echo
var_dump($parse_date) ."<br>";
//here you will receive hours as 00 minutes as 14 and seconds as 0. The error will get set as the same as above. Meaning "Unexpected character"
?>
up
-5
alan at wilcoxengineering dot com
14 years ago
Caution: date_parse expects months 1..12 only.

date_parse("13/1/5769")  for  month=13, Ehul in Jewish calendar, results in  month==3 instead of month==13.

It does, however, report the error array showing "Unexpected Character."

It would be nice if date_parse could handle the months properly (just report back a "13" for the month). The older approach of substr() is my workaround.
up
-4
eugene at ultimatecms dot co dot za
14 years ago
<?php

$ida
= '091122671325';
$idb = '091123671325';

// This function will match the identity number up to the day, but only for a maximum of 99years+364days.
// Will not work when checking persons older than 100years-1day.

function idtodate($id)
{
       
$year = date("Y");
       
$month = date("m");
       
$day = date("d");

       
$nc = substr($year, 0, 2);
       
$ny = substr($year, 2, 2);

       
$y = substr($id, 0, 2);
       
$m = substr($id, 2, 2);
       
$d = substr($id, 4, 2);

        if(
$y.$m.$d <= $ny.$month.$day-1) {
               
$newc = $nc;
        } else {
               
$newc = $nc-1;
        }

       
$new = $newc.$y;

        return array(
'year' => $new, 'month' => $m, 'day' => $d);
}

echo
'ID: '.$ida.'<br>';
print_r(idtodate($ida));

echo
'<br><br>';

echo
'ID: '.$idb.'<br>';
print_r(idtodate($idb));

?>

Output:
1. If the year-month-day is smaller than today (2009-11-23), but bigger than 1999: year => 2009
ID: 091122671325
Array ( [year] => 2009 [month] => 11 [day] => 22 )

2. If the year-month-day is the same as, or bigger than today, but smaller than 2000: year => 1909
ID: 091123671325
Array ( [year] => 1909 [month] => 11 [day] => 23 )
To Top