Beware that fxImage return value's type is a new object(Imagick), opposing the current documentation (boolean). Therefore it does not affect the caller object. Example:
<?php
$canvas = new Imagick();
$canvas->newImage(256, 256, "white", "jpg");
$gradient = new Imagick();
$gradient->newPseudoImage(256, 256, "gradient:white-black");
$canvas->compositeImage( $gradient, imagick::COMPOSITE_OVER, 0, 0 );
$canvas->rotateImage(new ImagickPixel(), 90);
/*instead of just $canvas->fxImage("floor(s*10+0.5)/10"); we must store fxImage()'s result*/
$canvas= $canvas->fxImage("floor(s*10+0.5)/10");
header( "Content-Type: image/jpg" );
echo $canvas;
?>
Imagick::fxImage
(PECL imagick 2, PECL imagick 3)
Imagick::fxImage — Evaluate expression for each pixel in the image
Descrierea
public Imagick::fxImage
( string
$expression
[, int $channel = Imagick::CHANNEL_DEFAULT
] ) : ImagickEvaluate expression for each pixel in the image. Consult » The Fx Special Effects Image Operator for more information.
Parametri
-
expression -
The expression.
-
channel -
Provide any channel constant that is valid for your channel mode. To apply to more than one channel, combine channeltype constants using bitwise operators. Refer to this list of channel constants.
Valorile întoarse
Întoarce true în caz de succes.
Erori/Excepții
Emite ImagickException în caz de eroare.
Exemple
Example #1 Imagick::fxImage()
<?php
function fxImage() {
$imagick = new \Imagick();
$imagick->newPseudoImage(200, 200, "xc:white");
$fx = 'xx=i-w/2; yy=j-h/2; rr=hypot(xx,yy); (.5-rr/140)*1.2+.5';
$fxImage = $imagick->fxImage($fx);
header("Content-Type: image/png");
$fxImage->setimageformat('png');
echo $fxImage->getImageBlob();
}
?>
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User Contributed Notes 1 note
thomasgf22 at NOSPAM dot gmail dot com ¶
9 years ago
