is_a

(PHP 4 >= 4.2.0, PHP 5, PHP 7)

is_aChecks if the object is of this class or has this class as one of its parents

Descrierea

is_a ( mixed $object , string $class_name [, bool $allow_string = false ] ) : bool

Checks if the given object is of this class or has this class as one of its parents.

Parametri

object

A class name or an object instance.

class_name

The class name

allow_string

If this parameter set to false, string class name as object is not allowed. This also prevents from calling autoloader if the class doesn't exist.

Valorile întoarse

Returns true if the object is of this class or has this class as one of its parents, false otherwise.

Exemple

Example #1 is_a() example

<?php
// define a class
class WidgetFactory
{
  var 
$oink 'moo';
}

// create a new object
$WF = new WidgetFactory();

if (
is_a($WF'WidgetFactory')) {
  echo 
"yes, \$WF is still a WidgetFactory\n";
}
?>

Example #2 Using the instanceof operator in PHP 5

<?php
if ($WF instanceof WidgetFactory) {
    echo 
'Yes, $WF is a WidgetFactory';
}
?>

A se vedea și

  • get_class() - Returns the name of the class of an object
  • get_parent_class() - Retrieves the parent class name for object or class
  • is_subclass_of() - Checks if the object has this class as one of its parents or implements it

add a note add a note

User Contributed Notes 7 notes

up
44
Ronald Locke
7 years ago
Please note that you have to fully qualify the class name in the second parameter.

A use statement will not resolve namespace dependencies in that is_a() function.

<?php
namespace foo\bar;

class
A {};
class
B extends A {};
?>

<?php
namespace har\var;

use
foo\bar\A;
$foo = new foo\bar\B();

is_a($foo, 'A'); // returns false;
is_a($foo, 'foo\bar\A'); // returns true;
?>

Just adding that note here because all examples are without namespaces.
up
33
Aron Budinszky
12 years ago
Be careful! Starting in PHP 5.3.7 the behavior of is_a() has changed slightly: when calling is_a() with a first argument that is not an object, __autoload() is triggered!

In practice, this means that calling is_a('23', 'User'); will trigger __autoload() on "23". Previously, the above statement simply returned 'false'.

More info can be found here:
https://bugs.php.net/bug.php?id=55475

Whether this change is considered a bug and whether it will be reverted or kept in future versions is yet to be determined, but nevertheless it is how it is, for now...
up
13
p dot scheit at zweipol dot net
17 years ago
At least in PHP 5.1.6 this works as well with Interfaces.

<?php
interface test {
  public function
A();
}

class
TestImplementor implements test {
  public function
A () {
    print
"A";
  }
}

$testImpl = new TestImplementor();

var_dump(is_a($testImpl,'test'));
?>

will return true
up
7
cesoid at yahoo dot com
18 years ago
is_a returns TRUE for instances of children of the class.

For example:

class Animal
{}

class Dog extends Animal
{}

$test = new Dog();

In this example is_a($test, "Animal") would evaluate to TRUE as well as is_a($test, "Dog").

This seemed intuitive to me, but did not seem to be documented.
up
1
dkrupyanskiy[at]gmail
6 years ago
Looks like the function signature given in description is wrong. Actually it can take a string  as a first parameter in the case if $allow_string is set to true.

It took some time to find out how the last parameter should be used. Please consider the following example

<?php

class Foo{}

spl_autoload_register(
    function(
$classname){
       
printf('autoload has been triggered for %s%s', $classname, PHP_EOL);
    }
);

var_dump(is_a('UndefinedClassName', Foo::class, true));

?>
up
0
eitan at mosenkis dot net
12 years ago
As of PHP 5.3.9, is_a() seems to return false when passed a string for the first argument. Instead, use is_subclass_of() and, if necessary for your purposes, also check if the two arguments are equal, since is_subclass_of('foo', 'foo') will return false, while is_a('foo', 'foo') used to return true.
up
-20
portugal {at} jawira {dot} com
8 years ago
I just want to point out that you can replace "is_a()" function with the "instanceof" operator, BUT you must use a variable to pass the class name string.

This will work:
<?php
$object
= new \stdClass();
$class_name = '\stdClass';

var_dump(is_a($object, $class_name));     // bool(true)
var_dump(is_a($object, '\stdClass'));     // bool(true)
var_dump($object instanceof $class_name); // bool(true)
?>

While this don't:
<?php
$object
= new \stdClass();
var_dump($object instanceof '\stdClass'); // Parse error: syntax error, unexpected ''\stdClass'' (T_CONSTANT_ENCAPSED_STRING)
?>
To Top