mysqli_stmt::$param_count

mysqli_stmt_param_count

(PHP 5, PHP 7)

mysqli_stmt::$param_count -- mysqli_stmt_param_countReturns the number of parameter for the given statement

설명

객체 기반 형식

절차식 형식

int mysqli_stmt_param_count ( mysqli_stmt $stmt )

Returns the number of parameter markers present in the prepared statement.

인수

stmt

순차 형식 전용: mysqli_stmt_init()가 반환한 statement 식별자.

반환값

Returns an integer representing the number of parameters.

예제

Example #1 객체 기반 형식

<?php
$mysqli 
= new mysqli("localhost""my_user""my_password""world");

/* check connection */
if (mysqli_connect_errno()) {
    
printf("Connect failed: %s\n"mysqli_connect_error());
    exit();
}

if (
$stmt $mysqli->prepare("SELECT Name FROM Country WHERE Name=? OR Code=?")) {

    
$marker $stmt->param_count;
    
printf("Statement has %d markers.\n"$marker);

    
/* close statement */
    
$stmt->close();
}

/* close connection */
$mysqli->close();
?>

Example #2 절차식 형식

<?php
$link 
mysqli_connect("localhost""my_user""my_password""world");

/* check connection */
if (mysqli_connect_errno()) {
    
printf("Connect failed: %s\n"mysqli_connect_error());
    exit();
}

if (
$stmt mysqli_prepare($link"SELECT Name FROM Country WHERE Name=? OR Code=?")) {

    
$marker mysqli_stmt_param_count($stmt);
    
printf("Statement has %d markers.\n"$marker);

    
/* close statement */
    
mysqli_stmt_close($stmt);
}

/* close connection */
mysqli_close($link);
?>

위 예제들의 출력:

Statement has 2 markers.

참고

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User Contributed Notes 1 note

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1
Senthryl
12 years ago
This parameter (and presumably any other parameter in mysqli_stmt) will raise an error with the message "Property access is not allowed yet" if the statement was not prepared properly, or not prepared at all.

To prevent this, always ensure that the return value of the "prepare" statement is true before accessing these properties.
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