Ds\Set::xor

(PECL ds >= 1.0.0)

Ds\Set::xorCreates a new set using values in either the current instance or in another set, but not in both.

설명

public Ds\Set Ds\Set::xor ( Ds\Set $set )

Creates a new set containing values in the current instance as well as another set, but not in both.

A ⊖ B = {x : x ∈ (A \ B) ∪ (B \ A)}

인수

set

The other set.

반환값

A new set containing values in the current instance as well as another set, but not in both.

See Also

예제

Example #1 Ds\Set::xor() example

<?php
$a 
= new \Ds\Set([123]);
$b = new \Ds\Set([345]);

var_dump($a->xor($b));
?>

위 예제의 출력 예시:

object(Ds\Set)#3 (4) {
  [0]=>
  int(1)
  [1]=>
  int(2)
  [2]=>
  int(4)
  [3]=>
  int(5)
}
add a note add a note

User Contributed Notes

There are no user contributed notes for this page.
To Top