DateTime::getTimestamp

DateTimeImmutable::getTimestamp

DateTimeInterface::getTimestamp

date_timestamp_get

(PHP 5 >= 5.3.0, PHP 7)

DateTime::getTimestamp -- DateTimeImmutable::getTimestamp -- DateTimeInterface::getTimestamp -- date_timestamp_getGets the Unix timestamp

설명

객체 기반 형식

public int DateTime::getTimestamp ( void )
public int DateTimeImmutable::getTimestamp ( void )
public int DateTimeInterface::getTimestamp ( void )

절차식 형식

Gets the Unix timestamp.

인수

이 함수는 인수가 없습니다.

반환값

Returns the Unix timestamp representing the date.

예제

Example #1 DateTime::getTimestamp() example

객체 기반 형식

<?php
$date 
= new DateTime();
echo 
$date->getTimestamp();
?>

절차식 형식

<?php
$date 
date_create();
echo 
date_timestamp_get($date);
?>

위 예제들의 출력 예시:

1272509157

주의

Using U as the parameter to DateTime::format() is an alternative when using PHP 5.2.

참고

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User Contributed Notes 3 notes

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36
heiccih at gmail dot com
10 years ago
In 32-bit system the unix timestamp will overflow if the date goes beyond year 2038 and this method will return false. In 64-bit systems this function will still work as intended. For more information please see http://en.wikipedia.org/wiki/Year_2038_problem.
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36
Justin Heesemann
13 years ago
Note that for dates before the unix epoch getTimestamp() will return false, whereas format("U") will return a negative number.

<?php
$date
= new DateTime("1899-12-31");
// "-2209078800"
echo $date->format("U");
// false
echo $date->getTimestamp();
?>
up
-1
Julien Bornstein
3 years ago
Please note that DateTime::gettimestamp() will return an integer, but DateTime::format("U") will return a string.

timestamp must always be typed as int because in PHP, timestamps are integers.

eg:
- strftime ( string $format [, int $timestamp = time() ] ) : string
- time() // return int
- ...

So IMHO, as PHP becomes more and more a typed language, avoid using DateTime::format("U") to avoid this kind of errors "strftime() expects parameter 2 to be int, string given"
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