PHP 5.6.0beta1 released

mysql_fetch_row

(PHP 4, PHP 5)

mysql_fetch_rowOttiene una riga del risultato come un array enumerato

Descrizione

array mysql_fetch_row ( resource $risultato )

Restituisce un array che corrisponde ad una riga caricata oppure FALSE se non ci sono più righe.

mysql_fetch_row() carica una riga di dati dal risultato associato all'identificativo specificato. La riga è restituita com un array. Ogni colonna del risultato è memorizzata in un indice dell'array, partendo dall'indice 0.

La susseguente chiamata a mysql_fetch_row() restituisce la successiva riga nell'intervallo del risultato oppure FALSE se non ci sono più righe.

Vedere anche: mysql_fetch_array(), mysql_fetch_object(), mysql_data_seek(), mysql_fetch_lengths() e mysql_result().

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User Contributed Notes 7 notes

up
2
michael and then an at sign wassupy.com
11 years ago
to print an array, simply use print_r(array name)

like this:
    $myrow = mysql_fetch_row($result);
echo "<pre>";
print_r($myrow);
echo "</pre>";

this will output the array in a readable form, with the index, too. Don't forget the 'pre' tags or the output will be on a single line.
up
2
ryhan_balboa at yahoo dot com
6 years ago
The following are the basic codes to get a specific row from the mysql db into a $row variable:

 
$query = "SELECT * FROM table";
$result = mysql_query($query);
$row = mysql_fetch_row($result);

And $row[0], $row[1] ... $row[n] are used to access those field values.

Does anyone know how I can add a new field to $row, so that the field count increases from n to n+1?

I have tried treating $row like an array, and tried array_push function, but didn't work.

Thanks.
up
0
m dot s at programmers-online dot net
8 years ago
The following function to read all data out of a mysql-resultset, is may be faster than Rafaels solution:

<?
function mysql_fetch_all($result) {
   while(
$row=mysql_fetch_array($result)) {
      
$return[] = $row;
   }
   return
$return;
}
?>
up
0
a at simongrant dot org
12 years ago
Maybe worth pointing out that all the fields returned by this (and other?) calls are returned with type string. This had me puzzled for quite some time.
up
-1
pepik at gmail dot cz
9 months ago
<?php 
 
require 'prhlavicka.php';
 
pis_hlavicku('Vypis článků');        
   
   require_once
'db.php';
   
$kom = new server();
   
$sql=$kom->query("SELECT autor,nazev,obsah FROM `Clanky_Sadek`");
               while (
$data = mysql_fetch_row($sql)){
                 ECHO
'<br />--AUTOR--<br />'.$data[0].'<br />__NÁZEV ČLÁNKU__<br />'.$data[1].'<br />..OBSAH ČLÁNKU..<br />'.$data[2];     }   
 
  include
'Paticka.html'; ?>
up
-3
larkitetto at gmail dot com
6 years ago
sry :) note now fixed:

<?php
$esi
=mysql_list_tables($db);$ris=mysql_fetch_row($esi);
//example: $db has >= 1 tabs
echo var_dump($ris);
//echoes only array(1). solution:
while($ris=mysql_fetch_row($esi)) echo $ris[0];
/*debug:
$ris=array("1st_tab"); ... $ris=array("n_tab");$ris=false;*/
while ($ris[]=mysql_fetch_row($esi));
//debug:$ris=array(array("1st_tab"), ... array("n_tab"));
echo $ris[n][0];//echo:"n_tab"
echo $ris[0][n];//echo:array | null
?>

hope it helps
up
-6
jhulbert at redf dot com
4 years ago
Creates table from all db info:

<?php
$qry
= "SELECT * FROM exp_member_data";
$res = mysql_query($mem_qry);

function
mysql_fetch_all($res) {
   while(
$row=mysql_fetch_array($res)) {
      
$return[] = $row;
   }
   return
$return;
}

function
create_table($dataArr) {
    echo
"<tr>";
    for(
$j = 0; $j < count($dataArr); $j++) {
        echo
"<td>".$dataArr[$j]."</td>";
    }
    echo
"</tr>";
}

$all = mysql_fetch_all($res);

echo
"<table class='data_table'>";

for(
$i = 0; $i < count($all); $i++) {
   
create_table($all[$i]);
}

echo
"</table>";

?>
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