imagesettile

(PHP 4 >= 4.0.6, PHP 5, PHP 7, PHP 8)

imagesettileSet the tile image for filling

Descrizione

imagesettile(GdImage $image, GdImage $tile): bool

imagesettile() sets the tile image to be used by all region filling functions (such as imagefill() and imagefilledpolygon()) when filling with the special color IMG_COLOR_TILED.

A tile is an image used to fill an area with a repeated pattern. Any GD image can be used as a tile, and by setting the transparent color index of the tile image with imagecolortransparent(), a tile allows certain parts of the underlying area to shine through can be created.

Attenzione

You need not take special action when you are finished with a tile, but if you destroy the tile image (or let PHP destroy it), you must not use the IMG_COLOR_TILED color until you have set a new tile image!

Elenco dei parametri

image

Una risorsa immagine, restituita da una delle funzioni di creazione immagine, come imagecreatetruecolor().

tile

The image object to be used as a tile.

Valori restituiti

Restituisce true in caso di successo, false in caso di fallimento.

Log delle modifiche

Versione Descrizione
8.0.0 image and tile expect GdImage instances now; previously, resources were expected.

Esempi

Example #1 imagesettile() example

<?php
// Load an external image
$zend = imagecreatefromgif('./zend.gif');

// Create a 200x200 image
$im = imagecreatetruecolor(200, 200);

// Set the tile
imagesettile($im, $zend);

// Make the image repeat
imagefilledrectangle($im, 0, 0, 199, 199, IMG_COLOR_TILED);

// Output image to the browser
header('Content-Type: image/png');

imagepng($im);
imagedestroy($im);
imagedestroy($zend);
?>

Il precedente esempio visualizzerĂ  qualcosa simile a:

Output of example : imagesettile()

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User Contributed Notes 2 notes

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3
aquilo at xtram dot net
19 years ago
There is very little information about this function so I thought I'd add a few notes I found while trying to get this

working.

First make sure your version of PHP is above 4.3.2 I spent an hour searching goggles 13000+ mirrors of this same page and

finally found the info I needed at AltaVista, there is a bug in PHP 4.3.2 that makes this none functional.

if your creating the base image you need to create it with imageCreateTrueColor() if your using a PNG with transparency, I

found even nullifying the PNG's transparency with GD doesn't work. the tiling PNG has to be created without transparency to work with imageCreate(). but from what I've seen imageCreateFromXXX() can use transparent and nonetransparent PNG's.

here is an example.
<?php
    $diagramWidth
= 300;
   
$diagramHeight = 50;

   
$image = imageCreateTrueColor ($diagramWidth, $diagramHeight);
   
$imagebg = imageCreateFromPNG ('tile.png'); // transparent PNG

   
imageSetTile ($image, $imagebg);
   
imageFilledRectangle ($image, 0, 0, $diagramWidth, $diagramHeight, IMG_COLOR_TILED);

   
$textcolor1 = imageColorAllocate ($image, 80, 80, 80);
   
$textcolor2 = imageColorAllocate ($image, 255, 255, 255);

   
imageString ($image, 3, 10, 20, 'Transparent PNG Tile Test...', $textcolor1);
   
imageString ($image, 39, 19, 'Transparent PNG Tile Test...', $textcolor2);

   
Header("Content-type: image/png");
   
imagePNG ($image);

   
imagedestroy ($image);
   
imagedestroy ($imagebg);
?>

hope this helps someone else!
Aquilo
up
0
onion at ooer dot com
18 years ago
If you're using a tile image that has some form of transparency you'll need to make sure your destination image is set to use alpha blending. By default it will be, but if for any reason you've changed it you'll need to do:

imagealphablending($image,true);

before any operation using IMG_COLOR_TILED.
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