basename

(PHP 4, PHP 5, PHP 7)

basenameRestituisce il nome del file dal percorso indicato

Descrizione

string basename ( string $path [, string $suffix ] )

Data una stringa contenente il percorso di un file, questa funzione restituisce il nome del file. Se il nome del file finisce in suffix quest'ultimo verrà tagliato.

Su Windows, sia gli slash (/) che i backslash (\) vengono utilizzati come carattere di separazione delle directory. In altri ambienti, si usa solo lo slash semplice (/).

Example #1 Esempio di basename()

<?php
$path 
"/home/httpd/html/index.php";
$file basename($path);        // la variabile $file contiene "index.php"
$file basename($path,".php"); // la variabile $file contiene "index"
?>

Nota:

Il parametro suffix è stato aggiunto in PHP 4.1.0.

Vedere anche dirname()

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User Contributed Notes 27 notes

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11
stephane dot fidanza at gmail dot com
8 years ago
Support of the $suffix parameter has changed between PHP4 and PHP5:
in PHP4, $suffix is removed first, and then the core basename is applied.
conversely, in PHP5, $suffix is removed AFTER applying core basename.

Example:
<?php
  $file
= "path/to/file.xml#xpointer(/Texture)";
  echo
basename($file, ".xml#xpointer(/Texture)");
?>

Result in PHP4: file
Result in PHP5: Texture)
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4
leaksin [ at ] gmail [ dot ] com
2 years ago
This is a string function,too.
basename() does not check the current path for being exist or not.
It's great to use it for working with URL or search implement.
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1
lcvalentine at gmail dot com
8 months ago
@softontherocks at gmail dot com
> If you want to get the extension of a file, I posted a function in
> http://softontherocks.blogspot.com/2013/07/obtener-la-extension-de-un-fichero-con.html
>
> The function is:
>
> function getExtension($file) {
>   $pos = strrpos($file, '.');
>   return substr($file, $pos+1);
> }

This is much simpler:
$ext = strrchr( $filename, '.' );
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1
softontherocks at gmail dot com
8 months ago
If you want to get the extension of a file, I posted a function in http://softontherocks.blogspot.com/2013/07/obtener-la-extension-de-un-fichero-con.html

The function is:

function getExtension($file) {
  $pos = strrpos($file, '.');
  return substr($file, $pos+1);
}
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3
swedish boy
5 years ago
Here is a quick way of fetching only the filename (without extension) regardless of what suffix the file has.

<?php

// your file
$file = 'image.jpg';

$info = pathinfo($file);
$file_name basename($file,'.'.$info['extension']);

echo
$file_name; // outputs 'image'

?>
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2
zandor_zz at yahoo dot it
6 years ago
It might be useful to have a version of the function basename working with arrays too.

<?php
function a_basename( $file, $exts )
{
   
$onlyfilename = end( explode( "/", $file ) );

    if(
is_string( $exts ) )
    {
        if (
strpos( $onlyfilename, $exts, 0 ) !== false )
       
$onlyfilename = str_replace( $exts, "", $onlyfilename );
    }
    else if (
is_array( $exts ) )
    {
       
// works with PHP version <= 5.x.x
       
foreach( $exts as $KEY => $ext )
        {
           
$onlyfilename = str_replace( $ext, "", $onlyfilename );
        }
    }

    return
$onlyfilename ;
}
?>
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1
crash at subsection dot org dot uk
9 years ago
A simple way to return the current directory:
$cur_dir = basename(dirname($_SERVER[PHP_SELF]))

since basename always treats a path as a path to a file, e.g.

/var/www/site/foo/ indicates /var/www/site as the path to file
foo
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1
(remove) dot nasretdinov at (remove) dot gmail dot com
6 years ago
There is only one variant that works in my case for my Russian UTF-8 letters:

<?php
function mb_basename($file)
{
    return
end(explode('/',$file));
}
><

It is intented for UNIX servers
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1
lazy lester
9 years ago
If your path has a query string appended, and if the query string contains a "/" character, then the suggestions for extracting the filename offered below don't work.

For instance if the path is like this:
http://www.ex.com/getdat.php?dep=n/a&title=boss

Then both the php basename() function, and also
the $_SERVER[QUERY_STRING] variables get confused.

In such a case, use:

<php
$path_with_query="http://www.ex.com/getdat.php?dep=n/a&title=boss";
$path=explode("?",$path_with_query);
$filename=basename($path[0]);
$query=$path[1];
?>
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0
thoughts at highermind dot org
8 years ago
Basename without query string:

<?php
$filename   
= array_shift(explode('?', basename($url_path)));
?>
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-2
poop at poop dot com
8 months ago
@ lcvalentine at gmail dot com
>This is much simpler:
>$ext = strrchr( $filename, '.' );

Even though yours is shorter, you can also do:

$ext = end(explode(".", basename($file
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-1
amitabh at NOSPAM dot saysnetsoft dot com
10 years ago
The previous example posted by "pvollma" didn't work out for me, so I modified it slightly:
<?php
function GetFileName($file_name)
{
       
$newfile = basename($file_name);
        if (
strpos($newfile,'\\') !== false)
        {
               
$tmp = preg_split("[\\\]",$newfile);
               
$newfile = $tmp[count($tmp) - 1];
                return(
$newfile);
        }
        else
        {
                return(
$file_name);
        }
}
?>
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-1
KOmaSHOOTER at gmx dot de
10 years ago
If you want the current path where youre file is and not the full path then use this :)

<?php
echo('dir = '.basename (dirname($_SERVER['PHP_SELF']),"/"));   
// retuns the name of current used directory
?>

Example:

www dir: domain.com/temp/2005/january/t1.php

<?php
echo('dirname <br>'.dirname($_SERVER['PHP_SELF']).'<br><br>');   
// returns: /temp/2005/january
?>

<?php
echo('file = '.basename ($PHP_SELF,".php"));   
// returns: t1
?>

if you combine these two you get this
<?php
echo('dir = '.basename (dirname($_SERVER['PHP_SELF']),"/"));   
// returns: january
?>

And for the full path use this
<?php
echo(' PHP_SELF <br>'.$_SERVER['PHP_SELF'].'<br><br>');
// returns: /temp/2005/january/t1.php   
?>
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-1
KOmaSHOOTER at gmx dot de
11 years ago
Exmaple for exploding ;) the filename to an array

<?php
echo(basename ($PHP_SELF)."<br>");  // returnes filename.php
$file = basename ($PHP_SELF);
$file = explode(".",$file);
print_r($file);    // returnes Array ( [0] => filename [1] => php )
echo("<br>");
$filename = basename(strval($file[0]),$file[1]);
echo(
$filename."<br>");  // returnes  filename
echo(basename ($PHP_SELF,".php")."<br>");  // returnes  filename
echo("<br>");
echo(
"<br>");
//show_source(basename ($PHP_SELF,".php").".php")
show_source($file[0].".".$file[1])
?>
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-2
icewind
9 years ago
Because of filename() gets "file.php?var=foo", i use explode in addition to basename like here:

$file = "path/file.php?var=foo";
$file = explode("?", basename($file));
$file = $file[0];
$query = $file[1];

Now $file only contains "file.php" and $query contains the query-string (in this case "var=foo").
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-2
www.turigeza.com
9 years ago
simple but not said in the above examples

echo basename('somewhere.com/filename.php?id=2', '.php');
will output
filename.php?id=2

which is not the filename in case you expect!
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-3
adrian at foeder dot de
7 years ago
On windows systems, filenames are case-insensitive. If you have to make sure the right case is used when you port your application to an unix system, you may use a combination of the following:

<?php
//assume the real filename is mytest.JPG:

$name_i_have = "mytest.jpg";
$realfilename = basename(realpath($name_i_have));
?>

basename itself does not check the filesystem for the given file, it does, so it seems, only string-manipulation.
With realpath() you can "extend" this functionality.
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-1
pvollma at pcvsoftware dot net
10 years ago
There is a real problem when using this function on *nix servers, since it does not handle Windows paths (using the \ as a separator). Why would this be an issue on *nix servers? What if you need to handle file uploads from MS IE? In fact, the manual section "Handling file uploads" uses basename() in an example, but this will NOT extract the file name from a Windows path such as C:\My Documents\My Name\filename.ext. After much frustrated coding, here is how I handled it (might not be the best, but it works):

<?php
$filen
= stripslashes($_FILES['userfile']['name']);
$newfile = basename($filen);
if (
strpos($newfile,'\\') !== false) {
 
$tmp = preg_split("[\\\]",$newfile);
 
$newfile = $tmp[count($tmp) - 1];
}
?>

$newfile will now contain only the file name and extension, even if the POSTed file name included a full Windows path.
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-2
daijoubu_NOSP at M_videotron dot ca
11 years ago
An faster alternative to:

<?php
array_pop
(explode('.', $fpath));
?>

would be:

<?php
substr
($fpath, strrpos($fpath, '.')); // returns the dot
?>

If you don't want the dot, simply adds 1 to the position

<?php
substr
($fpath, strrpos($fpath, '.') + 1); // returns the ext only
?>
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-3
pai dot ravi at yahoo dot com
6 years ago
once you have extracted the basename from the full path and want to separate the extension from the file name, the following function will do it efficiently:

<?php
function splitFilename($filename)
{
   
$pos = strrpos($filename, '.');
    if (
$pos === false)
    {
// dot is not found in the filename
       
return array($filename, ''); // no extension
   
}
    else
    {
       
$basename = substr($filename, 0, $pos);
       
$extension = substr($filename, $pos+1);
        return array(
$basename, $extension);
    }
}
?>
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-3
Muhammad El-Saeed muhammad at elsaeed dot info
2 years ago
to get the base url of my website

function url(){
    $base_url = isset($_SERVER['HTTPS']) && strtolower($_SERVER['HTTPS']) !== 'off' ? 'https' : 'http';
    $base_url .= '://'. $_SERVER['HTTP_HOST'];
    $base_url .= str_replace(basename($_SERVER['SCRIPT_NAME']), '', $_SERVER['SCRIPT_NAME']); 
    return $base_url;
}
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-2
hello at haroonahmad dot co dot uk
6 years ago
I got a blank output from this code

$cur_dir = basename(dirname($_SERVER[PHP_SELF]))

suggested earlier by a friend here.

So anybody who wants to get the current directory path can use another technique that I use as

//suppose you're using this in pageitself.php page

$current_dir=dirname(realpath("pageitself.php"));

I hope it helps.
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-2
KOmaSHOOTER at gmx dot de
10 years ago
if you want the name of the parent directory
<?php
$_parenDir_path
= join(array_slice(split( "/" ,dirname($_SERVER['PHP_SELF'])),0,-1),"/").'/'; // returns the full path to the parent dir
$_parenDir basename ($_parenDir_path,"/"); // returns only the name of the parent dir
// or
$_parenDir2 = array_pop(array_slice(split( "/" ,dirname($_SERVER['PHP_SELF'])),0,-1)); // returns also only the name of the parent dir
echo('$_parenDir_path  = '.$_parenDir_path.'<br>');
echo(
'$_parenDir  = '.$_parenDir.'<br>');
echo(
'$_parenDir2  = '.$_parenDir2.'<br>');
?>
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-3
Anonymous
9 years ago
icewinds exmaple wouldn't work, the query part would contain the second char of the filename, not the query part of the url.
<?
$file
= "path/file.php?var=foo";
$file = explode("?", basename($file));
$query = $file[1];
$file = $file[0];
?>

That works better.
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-3
Anonymous
7 months ago
As already pointed out above, if a query string contains a '/' character, basename will not handle it well. But it can come really handy when you want to pass a url with query string to a funtion that copies/downloads the file using basename as local filename, by attaching  an extra query to the end of the url:

<?php
  $url
= 'http://example.com/url?with=query_string';
 
basename($url); // url?with=query_string
 
$url = $url . '&filename_for_basename=/desired_filename.ext';
 
basename($url); // desired_filename.ext
?>

Note: you can use the filename from the HTTP header (if present) to get the file with it's original filename.
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-3
pvollma at pcvsoftware dot net
10 years ago
Note that in my example below, I used the stripslashes function on the target string first because I was dealing with the POST array $_FILES. When creating this array, PHP will add slashes to any slashes it finds in the string, so these must be stripped out first before processing the file path. Then again, the only reason I can think of that basename() would fail is when dealing with Windows paths on a *nix server -- and the file upload via POST is the only situation I can think of that would require this. Obviously, if you are not dealing with these additional slashes, invoking stripslashes() first would remove the very separators you need extract the file name from the full path.
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-3
giovanni at giacobbi dot net
11 years ago
No comments here seems to take care about UNIX system files, which typically start with a dot, but they are not "extensions-only".
The following function should work with every file path. If not, please let me know at my email address.

<?php

function remove_ext($str) {
 
$noext = preg_replace('/(.+)\..*$/', '$1', $str);
  print
"input: $str\n";
  print
"output: $noext\n\n";
}

remove_ext("/home/joh.nny/test.php");
remove_ext("home/johnny/test.php");
remove_ext("weirdfile.");
remove_ext(".hiddenfile");
remove_ext("../johnny.conf");
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