PHP Unconference Europe 2015

array_uintersect

(PHP 5)

array_uintersectComputes the intersection of arrays, compares data by a callback function

Descrizione

array array_uintersect ( array $array1 , array $array2 [, array $... ], callable $value_compare_func )

Computes the intersection of arrays, compares data by a callback function.

Elenco dei parametri

array1

The first array.

array2

The second array.

value_compare_func

La funzione di confronto deve restituire un intero minore, uguale o maggiore di zero se il primo argomento è considerato essere minore, uguale o maggiore del secondo.

int callback ( mixed $a, mixed $b )

Valori restituiti

Returns an array containing all the values of array1 that are present in all the arguments.

Esempi

Example #1 array_uintersect() example

<?php
$array1 
= array("a" => "green""b" => "brown""c" => "blue""red");
$array2 = array("a" => "GREEN""B" => "brown""yellow""red");

print_r(array_uintersect($array1$array2"strcasecmp"));
?>

Il precedente esempio visualizzerà:

Array
(
    [a] => green
    [b] => brown
    [0] => red
)

Vedere anche:

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User Contributed Notes 1 note

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0
Nate at RuggFamily dot com
7 years ago
I want to stress that in the user function, you do need to return either a 1 or a -1 properly; you cannot simply return 0 if the results are equal and 1 if they are not. 

The following code is incorrect:

<?php
function myfunction($v1,$v2)
{
if (
$v1===$v2)
    {
    return
0;
    }
return
1;
}

$a1=array(1, 2, 4);
$a2=array(1, 3, 4);
print_r(array_uintersect($a1,$a2,"myfunction"));
?>

This code is correct:

<?php
function myfunction($v1,$v2)
{
if (
$v1===$v2)
    {
    return
0;
    }
if (
$v1 > $v2) return 1;
return -
1;
}
$a1=array(1, 2, 4);
$a2=array(1, 3, 4);
print_r(array_uintersect($a1,$a2,"myfunction"));
?>
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