In 32-bit system the unix timestamp will overflow if the date goes beyond year 2038 and this method will return false. In 64-bit systems this function will still work as intended. For more information please see http://en.wikipedia.org/wiki/Year_2038_problem.
DateTime::getTimestamp
date_timestamp_get
(PHP 5 >= 5.3.0)
DateTime::getTimestamp -- date_timestamp_get — Gets the Unix timestamp
Beskrivelse
Object oriented style
public int DateTime::getTimestamp
( void
)
Procedural style
Gets the Unix timestamp.
Parametre
This function has no parameters.
Returnerings Værdier
Returns the Unix timestamp representing the date.
Eksempler
Eksempel #1 DateTime::getTimestamp() example
Object oriented style
<?php
$date = new DateTime();
echo $date->getTimestamp();
?>
Procedural style
<?php
$date = date_create();
echo date_timestamp_get($date);
?>
The above examples will output something similar to:
1272509157
Noter
Using U as the parameter to DateTime::format() is an alternative when using PHP 5.2.
Se også
- DateTime::setTimestamp() - Sets the date and time based on an Unix timestamp
- DateTime::format() - Returns date formatted according to given format
add a note
User Contributed Notes 3 notes
heiccih at gmail dot com ¶
10 years ago
Justin Heesemann ¶
13 years ago
Note that for dates before the unix epoch getTimestamp() will return false, whereas format("U") will return a negative number.
<?php
$date = new DateTime("1899-12-31");
// "-2209078800"
echo $date->format("U");
// false
echo $date->getTimestamp();
?>
Julien Bornstein ¶
3 years ago
Please note that DateTime::gettimestamp() will return an integer, but DateTime::format("U") will return a string.
timestamp must always be typed as int because in PHP, timestamps are integers.
eg:
- strftime ( string $format [, int $timestamp = time() ] ) : string
- time() // return int
- ...
So IMHO, as PHP becomes more and more a typed language, avoid using DateTime::format("U") to avoid this kind of errors "strftime() expects parameter 2 to be int, string given"
