SQLite3::prepare

(PHP 5 >= 5.3.0)

SQLite3::prepare — Prepares an SQL statement for execution

说明

public SQLite3Stmt SQLite3::prepare ( string $query )

Prepares an SQL statement for execution and returns an SQLite3Stmt object.

参数

query: The SQL query to prepare.

返回值

Returns an SQLite3Stmt object on success 或者在失败时返回 FALSE.

范例

Example #1 SQLite3::prepare() example


<?php
unlink('mysqlitedb.db');
$db = new SQLite3('mysqlitedb.db');

$db->exec('CREATE TABLE foo (id INTEGER, bar STRING)');
$db->exec("INSERT INTO foo (id, bar) VALUES (1, 'This is a test')");

$stmt = $db->prepare('SELECT bar FROM foo WHERE id=:id');
$stmt->bindValue(':id', 1, SQLITE3_INTEGER);

$result = $stmt->execute();
var_dump($result->fetchArray());
?>

add a note User Contributed Notes SQLite3::prepare - [1 notes]

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pavel dot lisa at centrum dot cz ¶

2 years ago


SQLite3::prepare() will fail, if you pass in a WHERE clause (in the $query) referring to a non-existent column.

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