类型转换

PHP 在变量声明时不需要定义类型。在这种情况下,变量的类型由存储的值决定。也就是说,如果 string 赋值给 $var,然后 $var 的类型就是 string。之后将 int 值赋值给 $var,它将是 int 类型。

PHP 可能会尝试在某些上下文中自动将值转换为另一种类型。不同的上下文有:

  • Numeric
  • String
  • Logical
  • Integral and string
  • Comparative
  • Function

注意: 当值需要解释为不同类型时,值本身会改变类型。

强制将变量当做某种变量来求值,参见类型转换一节。要更改变量的类型,请参阅 settype() 函数。

Numeric contexts

This is the context when using an arithmetical operator.

在这种情况下,如果任一运算对象是 float(或者不能解释为 int),则两个运算对象都将解释为 float,结果也将是 float。否则,运算对象将解释为 int,结果也将是 int。自 PHP 8.0.0 起,如果无法解释其中一个运算对象,则会抛出 TypeError

String contexts

This is the context when using echo, print, string interpolation, or the string concatenation operator.

这种情况下,值将会解释为 string。如果值无法解释,那么会抛出 TypeError。在 PHP 7.4.0 之前,会引发 E_RECOVERABLE_ERROR

Logical contexts

This is the context when using conditional statements, the ternary operator, or a logical operator.

在这种情况下,值将会解释为 bool

Integral and string contexts

This is the context when using bitwise operators.

在这种情况下,如果所有的运算对象都是 string,则结果也将是 string。否则运算对象将解释为 int,结果也将是 int。如果其中一个运算对象无法解释,则会抛出 TypeError

Comparative contexts

This is the context when using a comparison operator.

在此上下文中发生的类型转换在比较多种类型中进行了说明。

Function contexts

This is the context when a value is passed to a typed parameter, property, or returned from a function which declares a return type.

在此上下文中,值必须是类型值。但存在两个例外,第一个是如果值为 int,但声明的类型是 float,然后整数会转换为浮点数。第二个是如果声明的类型是 scalar 类型,值可转换为标量类型,并且强制类型模式处于活动状态(默认),值会转换为可接受的标量值。参见下文查看有关此行为的描述。

警告

内部函数自动将 null 转换为标量类型,此行为自 PHP 8.1.0 起弃用

使用简单类型声明的强制类型

  • bool 类型声明:值将解释为 bool
  • int 类型声明:如果明确定义转换,则值将解释为 int。例如,字符串是数字
  • float 类型声明:如果明确定义转换,则值将解释为 float。例如,字符串是数字
  • string 类型声明:值将解释为 string

使用联合类型的强制类型

When strict_types is not enabled, scalar type declarations are subject to limited implicit type coercions. 如果值的精确类型不是联合的一部分,然后会按照以下优先顺序选择目标类型:

  1. int
  2. float
  3. string
  4. bool
If the type exists in the union and the value can be coerced to the type under PHP's existing type-checking semantics, then the type is chosen. Otherwise, the next type is tried.

警告

一个例外,如果值是字符串,并且 int 和 float 都是联合类型的一部分,首选类型则通过现有的数字字符串语义决定。例如 "42" 选择 int"42.0" 选择 float

注意:

Types that are not part of the above preference list are not eligible targets for implicit coercion. In particular no implicit coercions to the null, false, and true types occur.

示例 #1 Example of types being coerced into a type part of the union

<?php
// int|string
42 --> 42 // exact type
"42" --> "42" // exact type
new ObjectWithToString --> "Result of __toString()"
// object never compatible with int, fall back to string
42.0 --> 42 // float compatible with int
42.1 --> 42 // float compatible with int
1e100 --> "1.0E+100" // float too large for int type, fall back to string
INF --> "INF" // float too large for int type, fall back to string
true --> 1 // bool compatible with int
[] --> TypeError // array not compatible with int or string

// int|float|bool
"45" --> 45 // int numeric string
"45.0" --> 45.0 // float numeric string

"45X" --> true // not numeric string, fall back to bool
"" --> false // not numeric string, fall back to bool
"X" --> true // not numeric string, fall back to bool
[] --> TypeError // array not compatible with int, float or bool
?>

类型转换

类型转换通过在值前面的括号中写入类型来将值转换指定的类型。

<?php
$foo
= 10; // $foo 是 int
$bar = (bool) $foo; // $bar 是 bool
?>

允许的转换是:

  • (int) ——转换为 int
  • (bool) ——转换为 bool
  • (float) ——转换为 float
  • (string) ——转换为 string
  • (array) ——转换为 array
  • (object) ——转换为 object
  • (unset) ——转换为 NULL

注意:

(integer)(int) 转换的别名。(boolean)(bool) 转换的别名。(binary)(string) 转换的别名。(double)(real)(float) 转换的别名。这些转换不使用标准的类型名称,不推荐使用。

警告

自 PHP 8.0.0 起弃用 (real) 转换别名。

警告

自 PHP 7.2.0 起弃用 (unset) 转换。注意 (unset) 转换等同于将值 NULL 通过赋值或者调用给变量。自 PHP 8.0.0 起移除 unset 转换。

警告

向前兼容 (binary) 转换和 b 前缀转换。注意 (binary) 转换和 (string) 相同,但是这可能会改变且不应依赖。

注意:

类型转换的括号中的空格将被忽略。 因此,以下两个转换是等价的:

<?php
$foo
= (int) $bar;
$foo = ( int ) $bar;
?>

将文字 string 和变量转换为二进制 string

<?php
$binary
= (binary) $string;
$binary = b"binary string";
?>

注意: 除了将变量转换为 string 之外,还可以将变量放在双引号内。

<?php
$foo
= 10; // $foo 是 int
$str = "$foo"; // $str 是 string
$fst = (string) $foo; // $fst 也是 string

// 打印出 "they are the same"
if ($fst === $str) {
echo
"they are the same";
}
?>

有时在类型之间转换时确切地会发生什么可能不是很明显。更多信息见如下不分:

注意: 因为 PHP 的 string 支持使用与 array 索引相同的语法,通过偏移量进行索引,所以以下示例适用于所有 PHP 版本:

<?php
$a
= 'car'; // $a 是 string
$a[0] = 'b'; // $a 依然是 string
echo $a; // bar
?>
请查看章节标题为存取和修改字符串中的字符获取更多信息。

add a note add a note

User Contributed Notes 36 notes

up
70
Raja
19 years ago
Uneven division of an integer variable by another integer variable will result in a float by automatic conversion -- you do not have to cast the variables to floats in order to avoid integer truncation (as you would in C, for example):

$dividend = 2;
$divisor = 3;
$quotient = $dividend/$divisor;
print $quotient; // 0.66666666666667
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12
Anonymous
5 years ago
"An example of PHP's automatic type conversion is the multiplication operator '*'. If either operand is a float, then both operands are evaluated as floats, and the result will be a float. Otherwise, the operands will be interpreted as integers, and the result will also be an integer. Note that this does not change the types of the operands themselves; the only change is in how the operands are evaluated and what the type of the expression itself is."

I understand what the doc is trying to say here, but this sentence is not correct as stated, other types can be coerced into floats.

e.g.

<?php
$a
= "1.5"; // $a is a string
$b = 100; // $b is an int
$c = $a * $b; // $c is a float, value is 150
// multiplication resulted in a float despite fact that neither operand was a float
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26
yury at krasu dot ru
21 years ago
incremental operator ("++") doesn't make type conversion from boolean to int, and if an variable is boolean and equals TRUE than after ++ operation it remains as TRUE, so:

$a = TRUE;
echo ($a++).$a;  // prints "11"
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22
fardelian
10 years ago
Casting objects to arrays is a pain. Example:

<?php

class MyClass {

    private
$priv = 'priv_value';
    protected
$prot = 'prot_value';
    public
$pub = 'pub_value';
    public
$MyClasspriv = 'second_pub_value';

}

$test = new MyClass();
echo
'<pre>';
print_r((array) $test);

/*
Array
(
    [MyClasspriv] => priv_value
    [*prot] => prot_value
    [pub] => pub_value
    [MyClasspriv] => second_pub_value
)
*/

?>

Yes, that looks like an array with two keys with the same name and it looks like the protected field was prepended with an asterisk. But that's not true:

<?php

foreach ((array) $test as $key => $value) {
   
$len = strlen($key);
    echo
"{$key} ({$len}) => {$value}<br />";
    for (
$i = 0; $i < $len; ++$i) {
        echo
ord($key[$i]) . ' ';
    }
    echo
'<hr />';
}

/*
MyClasspriv (13) => priv_value
0 77 121 67 108 97 115 115 0 112 114 105 118
*prot (7) => prot_value
0 42 0 112 114 111 116
pub (3) => pub_value
112 117 98
MyClasspriv (11) => second_pub_value
77 121 67 108 97 115 115 112 114 105 118
*/

?>

The char codes show that the protected keys are prepended with '\0*\0' and private keys are prepended with '\0'.__CLASS__.'\0' so be careful when playing around with this.
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19
Anonymous
21 years ago
Printing or echoing a FALSE boolean value or a NULL value results in an empty string:
(string)TRUE //returns "1"
(string)FALSE //returns ""
echo TRUE; //prints "1"
echo FALSE; //prints nothing!
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10
rmirabelle
13 years ago
The object casting methods presented here do not take into account the class hierarchy of the class you're trying to cast your object into.

/**
     * Convert an object to a specific class.
     * @param object $object
     * @param string $class_name The class to cast the object to
     * @return object
     */
    public static function cast($object, $class_name) {
        if($object === false) return false;
        if(class_exists($class_name)) {
            $ser_object     = serialize($object);
            $obj_name_len     = strlen(get_class($object));
            $start             = $obj_name_len + strlen($obj_name_len) + 6;
            $new_object      = 'O:' . strlen($class_name) . ':"' . $class_name . '":';
            $new_object     .= substr($ser_object, $start);
            $new_object     = unserialize($new_object);
            /**
             * The new object is of the correct type but
             * is not fully initialized throughout its graph.
             * To get the full object graph (including parent
             * class data, we need to create a new instance of
             * the specified class and then assign the new
             * properties to it.
             */
            $graph = new $class_name;
            foreach($new_object as $prop => $val) {
                $graph->$prop = $val;
            }
            return $graph;
        } else {
            throw new CoreException(false, "could not find class $class_name for casting in DB::cast");
            return false;
        }
    }
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2
Dhairya Lakhera
4 years ago
Value of uninitialized variable of different data types.

settype($a,'bool');
var_dump($a);         //boolean false

settype($b,'string');
var_dump($b);        //string '' (length=0)

settype($c,'array');
var_dump($c);        //array (size=0)  empty

settype($d,'int');
var_dump($d);       //int 0

settype($e,'float');
var_dump($e);      //float 0

settype($f,'object');
var_dump($f);     //object(stdClass)[1]
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11
ieee at REMOVE dot bk dot ru
11 years ago
There are some shorter and faster (at least on my machine) ways to perform a type cast.
<?php
$string
='12345.678';
$float=+$string;
$integer=0|$string;
$boolean=!!$string;
?>
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5
kuzawinski dot marcin at NOSPAM dot gmail dot com
9 years ago
You REALLY must be aware what you are doing, when you cast a lot  in your code. For example, you can accidentaly change FALSE to TRUE  (probably not in one line, like here):

if(TRUE === (boolean) (array) (int) FALSE) {
    kaboom();
}
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2
Anonymous
12 years ago
namaroulis stated "I found it tricky to check if a posted value was an integer"; to test if a variable is a number or a numeric string (such as form input, which is always a string), you must use is_numeric():

<?php
$_POST
['a'] = "42";

is_numeric( $_POST['a'] ); // true
?>
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2
martinscotta at gmail dot com
13 years ago
in response to bhsmither at gmail.com

It raises a warning because of the bad enquoted variable

<?php

error_reporting
( E_ALL | E_STRICT );

$foo['ten'] = 10;        // $foo['ten'] is an array holding an integer at key "ten"
$str = "{$foo['ten']}"// works "10"
$str = "$foo[ten]";      // DO NOT work!
up
2
wbcarts at juno dot com
15 years ago
WHERE'S THE BEEF?

Looks like type-casting user-defined objects is a real pain, and ya gotta be nuttin' less than a brain jus ta cypher-it. But since PHP supports OOP, you can add the capabilities right now. Start with any simple class.
<?php
class Point {
  protected
$x, $y;

  public function
__construct($xVal = 0, $yVal = 0) {
   
$this->x = $xVal;
   
$this->y = $yVal;
  }
  public function
getX() { return $this->x; }
  public function
getY() { return $this->y; }
}

$p = new Point(25, 35);
echo
$p->getX();      // 25
echo $p->getY();      // 35
?>
Ok, now we need extra powers. PHP gives us several options:
  A. We can tag on extra properties on-the-fly using everyday PHP syntax...
    $p->z = 45; // here, $p is still an object of type [Point] but gains no capability, and it's on a per-instance basis, blah.
  B. We can try type-casting it to a different type to access more functions...
    $p = (SuperDuperPoint) $p; // if this is even allowed, I doubt it. But even if PHP lets this slide, the small amount of data Point holds would probably not be enough for the extra functions to work anyway. And we still need the class def + all extra data. We should have just instantiated a [SuperDuperPoint] object to begin with... and just like above, this only works on a per-instance basis.
  C. Do it the right way using OOP - and just extend the Point class already.
<?php
class Point3D extends Point {
  protected
$z;                                // add extra properties...

 
public function __construct($xVal = 0, $yVal = 0, $zVal = 0) {
   
parent::__construct($xVal, $yVal);
   
$this->z = $zVal;
  }
  public function
getZ() { return $this->z; }  // add extra functions...
}

$p3d = new Point3D(25, 35, 45);  // more data, more functions, more everything...
echo $p3d->getX();               // 25
echo $p3d->getY();               // 35
echo $p3d->getZ();               // 45
?>
Once the new class definition is written, you can make as many Point3D objects as you want. Each of them will have more data and functions already built-in. This is much better than trying to beef-up any "single lesser object" on-the-fly, and it's way easier to do.
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2
edgar dot klerks at gmail dot com
15 years ago
It seems (unset) is pretty useless. But for people who like to make their code really compact (and probably unreadable). You can use it to use an variable and unset it on the same line:

Without cast:

<?php

$hello
= 'Hello world';
print
$hello;
unset(
$hello);

?>

With the unset cast:

<?php

$hello
= 'Hello world';
$hello = (unset) print $hello;

?>

Hoorah, we lost another line!
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2
miracle at 1oo-percent dot de
18 years ago
If you want to convert a string automatically to float or integer (e.g. "0.234" to float and "123" to int), simply add 0 to the string - PHP will do the rest.

e.g.

$val = 0 + "1.234";
(type of $val is float now)

$val = 0 + "123";
(type of $val is integer now)
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2
Anonymous
13 years ago
Checking for strings to be integers?
How about if a string is a float?

<?php

/* checks if a string is an integer with possible whitespace before and/or after, and also isolates the integer */
$isInt=preg_match('/^\s*([0-9]+)\s*$/', $myString, $myInt);

echo
'Is Integer? ',  ($isInt) ? 'Yes: '.$myInt[1] : 'No', "\n";

/* checks if a string is an integer with no whitespace before or after  */
$isInt=preg_match('/^[0-9]+$/', $myString);

echo
'Is Integer? ',  ($isInt) ? 'Yes' : 'No', "\n";

/* When checking for floats, we assume the possibility of no decimals needed.  If you MUST require decimals (forcing the user to type 7.0 for example) replace the sequence:
[0-9]+(\.[0-9]+)?
with
[0-9]+\.[0-9]+
*/

/* checks if a string is a float with possible whitespace before and/or after, and also isolates the number */
$isFloat=preg_match('/^\s*([0-9]+(\.[0-9]+)?)\s*$/', $myString, $myNum);

echo
'Is Number? ',  ($isFloat) ? 'Yes: '.$myNum[1] : 'No', "\n";

/* checks if a string is a float with no whitespace before or after */
$isInt=preg_match('/^[0-9]+(\.[0-9]+)?$/', $myString);

echo
'Is Number? ',  ($isFloat) ? 'Yes' : 'No', "\n";

?>
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2
Anonymous
3 years ago
Cast operators have a very high precedence, for example (int)$a/$b is evaluated as ((int)$a)/$b, not as (int)($a/$b) [which would be like intdiv($a,$b) if both $a and $b are integers].
The only exceptions (as of PHP 8.0) are the exponentiation operator ** [i.e. (int)$a**$b is evaluated as (int)($a**$b) rather than ((int)$a)**$b] and the special access/invocation operators ->, ::, [] and () [i.e. in each of (int)$a->$b, (int)$a::$b, (int)$a[$b] and (int)$a($b), the cast is performed last on the result of the variable expression].
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1
lucazd at gmail dot com
15 years ago
@alexgr (20-Jun-2008)

Correct me if I'm wrong, but that is not a cast, it might be useful sometimes, but the IDE will not reflect what's really happening:

<?php
class MyObject {
   
/**
     * @param MyObject $object
     * @return MyObject
     */
   
static public function cast(MyObject $object) {
        return
$object;
    }
   
/** Does nothing */
   
function f() {}
}

class
X extends MyObject {
   
/** Throws exception */
   
function f() { throw new exception(); }
}

$x = MyObject::cast(new X);
$x->f(); // Your IDE tells 'f() Does nothing'
?>

However, when you run the script, you will get an exception.
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1
namaroulis at gmail dot com
13 years ago
I found it tricky to check if a posted value was an integer.

<?php

$_POST
['a'] = "42";

is_int( $_POST['a'] ); //false
is_int( intval( "anything" ) ); //always true
?>

A method I use for checking if a string represents an integer value.

<?php
function check_int( $str )
                {
                    return 
is_numeric( $str ) && intval( $str ) - $str == 0;
                }
?>
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1
jphansen at uga dot edu
12 years ago
Type casting from string to int and vice versa is probably the most common conversation. PHP does this very simply through the +. and .= operators, removing any explicit casting:

<?php
$x
= 1;
var_dump($x); // int(1)
$x .= 1;
var_dump($x); // string(2) "11"; also an empty string ("") would cast to string without changing $x

$x = "1";
var_dump($x);  // string(1) "1"
$x += 1;
var_dump($x); // int(2); also a zero value (0) would cast to int without changing $x
?>
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1
Anonymous
18 years ago
If you have a boolean, performing increments on it won't do anything despite it being 1.  This is a case where you have to use a cast.

<html>
<body> <!-- don't want w3.org to get mad... -->
<?php
$bar
= TRUE;
?>
I have <?=$bar?> bar.
<?php
$bar
++;
?>
I now have <?=$bar?> bar.
<?php
$bar
= (int) $bar;
$bar++;
?>
I finally have <?=$bar?> bar.
</body>
</html>

That will print

I have 1 bar.
I now have 1 bar.
I finally have 2 bar.
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0
hemi68 at hotmail dot com
12 years ago
Cast a string to binary using PHP < 5.2.1

$binary = unpack('c*', $string);
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0
bhsmither at gmail.com
13 years ago
<?php
$foo
['ten'] = 10;            // $foo['ten'] is an array holding an integer at key "ten"
$str = "$foo['ten']";        // throws T_ENCAPSED_AND_WHITESPACE error
$str = "$foo[ten]";          // works because constants are skipped in quotes
$fst = (string) $foo['ten']; // works with clear intention
?>
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0
hek at theeks dot net
15 years ago
It would be useful to know the precedence (for lack of a better word) for type juggling.  This entry currently explains that "if either operand is a float, then both operands are evaluated as floats, and the result will be a float" but could (and I think should) provide a hierarchy that indicates, for instance, "between an int and a boolean, int wins; between a float and an int, float wins; between a string and a float, string wins" and so on (and don't count on my example accurately capturing the true hierarchy, as I haven't actually done the tests to figure it out).  Thanks!
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0
alexgr at gmail dot com
15 years ago
For a Cast to a User Defined Object you can define a cast method:

class MyObject {
    /**
     * @param MyObject $object
     * @return MyObject
     */
    static public function cast(MyObject $object) {
        return $object;
    }
}

In your php page code you can:
$myObject = MyObject::cast($_SESSION["myObject"]);

Then, PHP will validate the value and your IDE will help you.
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0
toma at smartsemantics dot com
19 years ago
In my much of my coding I have found it necessary to type-cast between objects of different class types.

More specifically, I often want to take information from a database, convert it into the class it was before it was inserted, then have the ability to call its class functions as well.

The following code is much shorter than some of the previous examples and seems to suit my purposes.  It also makes use of some regular expression matching rather than string position, replacing, etc.  It takes an object ($obj) of any type and casts it to an new type ($class_type).  Note that the new class type must exist:

function ClassTypeCast(&$obj,$class_type){
    if(class_exists($class_type,true)){
        $obj = unserialize(preg_replace"/^O:[0-9]+:\"[^\"]+\":/i",
          "O:".strlen($class_type).":\"".$class_type."\":", serialize($obj)));
    }
}
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0
philip_snyder at hotmail dot com
20 years ago
Re: the typecasting between classes post below... fantastic, but slightly flawed. Any class name longer than 9 characters becomes a problem... SO here's a simple fix:

function typecast($old_object, $new_classname) {
  if(class_exists($new_classname)) {
    // Example serialized object segment
    // O:5:"field":9:{s:5:...   <--- Class: Field
    $old_serialized_prefix  = "O:".strlen(get_class($old_object));
    $old_serialized_prefix .= ":\"".get_class($old_object)."\":";

    $old_serialized_object = serialize($old_object);
    $new_serialized_object = 'O:'.strlen($new_classname).':"'.$new_classname . '":';
    $new_serialized_object .= substr($old_serialized_object,strlen($old_serialized_prefix));
   return unserialize($new_serialized_object);
  }
  else
   return false;
}

Thanks for the previous code. Set me in the right direction to solving my typecasting problem. ;)
up
-1
Eric Lavoie
9 years ago
(array) null
array(null)

are not the same.

var_dump((array) null) =>
array (size=0)
  empty

var_dump(array (null)) =>
array (size=1)
  0 => null
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-1
berniev
8 years ago
May be expected, but not stated ..
Casting to the existing (same) type has no effect.
$t = 'abc';          // string 'abc'
$u=(array) $t;   // array 0 => string 'abc'  <-- now an array
$v=(array) $u;  // array 0 => string 'abc'  <-- unchanged
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-2
mbrowne83 (at GM)
9 years ago
The code listed in some of the comments here for supposedly "casting" from one class to another using unserialize/serialize does not actually change the class of the existing object; it creates a new object. So it's not the same as a cast.
up
-4
tom5025_ at hotmail dot com
19 years ago
function strhex($string)
{
   $hex="";
   for ($i=0;$i<strlen($string);$i++)
       $hex.=dechex(ord($string[$i]));
   return $hex;
}
function hexstr($hex)
{
   $string="";
   for ($i=0;$i<strlen($hex)-1;$i+=2)
       $string.=chr(hexdec($hex[$i].$hex[$i+1]));
   return $string;
}

to convert hex to str and vice versa
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-4
post_at_henribeige_dot_de
20 years ago
If you want to do not only typecasting between basic data types but between classes, try this function. It converts any class into another. All variables that equal name in both classes will be copied.

function typecast($old_object, $new_classname) {
  if(class_exists($new_classname)) {
    $old_serialized_object = serialize($old_object);
    $new_serialized_object = 'O:' . strlen($new_classname) . ':"' . $new_classname . '":' .
                             substr($old_serialized_object, $old_serialized_object[2] + 7);
    return unserialize($new_serialized_object);
  }
  else
    return false;
}

Example:

class A {
  var $secret;
  function A($secret) {$this->secret = $secret;}
  function output() {echo("Secret class A: " . $this->secret);}
}

class B extends A {
  var $secret;
  function output() {echo("Secret class B: " . strrev($this->secret));}
}

$a = new A("Paranoia");
$b = typecast($a, "B");

$a->output();
$b->output();
echo("Classname \$a: " . get_class($a) . "Classname \$b: " . get_class($b));

Output of the example code above:

Secret class A: Paranoia
Secret class B: aionaraP
Classname $a: a
Classname $b: b
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-4
dimo dot vanchev at bianor dot com
20 years ago
For some reason the code-fix posted by philip_snyder at hotmail dot com [27-Feb-2004 02:08]
didn't work for me neither with long_class_names nor with short_class_names. I'm using PHP v4.3.5 for Linux.
Anyway here's what I wrote to solve the long_named_classes problem:

<?php
function typecast($old_object, $new_classname) {
    if(
class_exists($new_classname)) {
       
$old_serialized_object = serialize($old_object);
       
$old_object_name_length = strlen(get_class($old_object));
       
$subtring_offset = $old_object_name_length + strlen($old_object_name_length) + 6;
       
$new_serialized_object  = 'O:' . strlen($new_classname) . ':"' . $new_classname . '":';
       
$new_serialized_object .= substr($old_serialized_object, $subtring_offset);
        return
unserialize($new_serialized_object);
     } else {
         return
false;
     }
}
?>
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-6
nullhilty at gmail dot com
15 years ago
Just a little experiment on the (unset) type cast:

<?php
$var
= 1;
$var_unset = (unset) $var;
$var_ref_unset &= (unset) $var;
var_dump($var);
var_dump($var_unset);
var_dump($var_ref_unset);
?>

output:
int(1)
NULL
int(0)
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-6
davaakhuu at outlook dot com
8 years ago
Type Juggling<br/>
   <?php $count = "2 cats"; ?>
   Type: <?php echo gettype($count); ?><br/>
   <?php $count += 3; ?>
   Type: <?php echo gettype($count); ?><br/>
   <?php $cats = "I have " . $count . "cats."; ?>
   Cats: <?php echo gettype($cats); ?><br/>
   <br/>
   Type Casting<br/>
   <?php settype($count, "integer"); ?>
   count: <?php echo gettype($count); ?><br/>

   <?php $count2 = (string)$count; ?>
   count: <?php echo gettype($count); ?><br/>
   count2: <?php echo gettype($count2); ?><br/>

   <?php $test1 = 3; ?>
   <?php $test2 = 3; ?>
   <?php settype($test1, "string"); ?>
   <?php (string)$test2; ?>
   test1: <?php echo gettype($test1); ?><br/>
   test2: <?php echo gettype($test2); ?><br/>
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-8
kajsunansis at that gmail
15 years ago
json_decode users consider this, when casting stdClass to array:
<?php
$obj
= new stdClass();
$obj->{"2"} = "id";
$arr = (array) $obj;
$result = isset($arr["2"]) || array_key_exists(2, $arr); // false
?>
..though casting is at least 2x faster than foreach.
up
-17
Jeffrey
15 years ago
IMAGINATION REQUIRED...

We can be a witness to PHP's 'type-jugglin' in real-time with a simple implementation of a MemoryMap. For the sake our purposes, pretend that this is an empty MemoryMap.
+-------+------+------+-------+
| index | $var | type | value |
+-------+------+------+-------+
|     1 |  --- | NULL |  null |
|     2 |  --- | NULL |  null |
|     3 |  --- | NULL |  null |
|     4 |  --- | NULL |  null |
+-------+------+------+-------+

<?php
# create some variables...
$a = 10;
$b = "Hello";
$c = array(55.45, 98.65);
# Now look at map...
?>
+-------+-------+---------+--------+
| index |  $var |    type |  value |
+-------+-------+---------+--------+
|     1 |    $a | INTEGER |     10 |
|     2 |    $b |  STRING |  Hello |
|     3 | $c[0] |   FLOAT |  55.45 |
|     4 | $c[1] |   FLOAT |  98.65 |
+-------+-------+---------+--------+
<?php
# Now, change the variable types...
$a = "Bye";
$b = 2;
$c[0] = "Buy";
$c[1] = "Now!";
#Look at map...
?>
+-------+-------+---------+--------+
| index |  $var |    type |  value |
+-------+-------+---------+--------+
|     1 |    $a |  STRING |    Bye | <- used to be INTEGER
|     2 |    $b | INTEGER |      2 | <- used to be STRING
|     3 | $c[0] |  STRING |    Buy | <- used to be FLOAT
|     4 | $c[1] |  STRING |  Right | <- used to be FLOAT
+-------+-------+---------+--------+
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