mysqli_result::free

mysqli_free_result

(PHP 5)

mysqli_result::free -- mysqli_free_resultFrees the memory associated with a result

Опис

Об'єктно-орієнтований стиль

void mysqli_result::free ( void )
void mysqli_result::close ( void )
void mysqli_result::free_result ( void )

Процедурний стиль

void mysqli_free_result ( mysqli_result $result )

Frees the memory associated with the result.

Зауваження:

You should always free your result with mysqli_free_result(), when your result object is not needed anymore.

Параметри

result

Procedural style only: A result set identifier returned by mysqli_query(), mysqli_store_result() or mysqli_use_result().

Значення, що повертаються

Не повертає значень.

Прогляньте Також

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User Contributed Notes 3 notes

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9
jack_action100 at hotmail dot example dot com
3 years ago
If you are STILL getting this error, even after freeing your results:
Internal SQL Bug: 2014, Commands out of sync; you can't run this command now

You may have a stored procedure in your query.   A procedure can return more than one result set, and it will always return one extra empty result set that carries some meta information on the procedure call itself, especially error information. ( source:  https://bugs.mysql.com/bug.php?id=71044 )

While calling single procedures, with one SELECT in them, using mysqli->query("CALL `stored_procedure`();"), I had to do the following to make it work between two calls:

<?php
$result
->free();
$mysqli->next_result();
?>

It has no negative impact if you are not calling a stored procedure.
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3
Vector at ionisis dot com
12 years ago
If you are getting this error:
Internal SQL Bug: 2014, Commands out of sync; you can't run this command now

Then you never called mysqli_result::free(), mysqli_result::free_result(), mysqli_result::close(), or mysqli_free_result() in your script, and must call it before executing another stored procedure.
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-24
Anonymous
12 years ago
Freeing the memory associated with a result means that the references returned by mysqli_fetch_object (or equivalent) are cleared. Thus if you should pass an object pointing to a database row _by reference_, every call of mysqli_free_result will discard the referenced data.
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