gzeof

(PHP 4, PHP 5)

gzeofTest for EOF on a gz-file pointer

Опис

int gzeof ( resource $zp )

Tests the given GZ file pointer for EOF.

Параметри

zp

The gz-file pointer. It must be valid, and must point to a file successfully opened by gzopen().

Значення, що повертаються

Returns TRUE if the gz-file pointer is at EOF or an error occurs; otherwise returns FALSE.

Приклади

Приклад #1 gzeof() example

<?php
$gz 
gzopen('somefile.gz''r');
while (!
gzeof($gz)) {
  echo 
gzgetc($gz);
}
gzclose($gz);
?>

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User Contributed Notes 2 notes

up
5
thomas at poindessous dot com
16 years ago
Be careful with this example. if gzopen doesn't return a valid handler, gzeof will do a nice loop.
up
-1
Anonymous
10 years ago
<?php
#fixed example
$gz = gzopen('somefile.gz', 'r');
while (
$gz && !gzeof($gz)) {
  echo
gzgetc($gz);
}
gzclose($gz);
?>
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