mysql_fetch_row

(PHP 4, PHP 5)

mysql_fetch_row — Get a result row as an enumerated array

Uyarı

Bu eklentinin kullanımı PHP 5.5.0 itibariyle önerilmemekte olup PHP 7.0.0'da kaldırılmıştır. Bu eklentinin yerine ya mysqli ya da PDO_MySQL eklentisi kullanılmalıdır. MySQL API seçerken MySQL API'ye Bakış belgesi yardımcı olabilir. Bu işlevin yerine kullanılabilecekler:

mysqli_fetch_row()
PDOStatement::fetch() with mode as PDO::FETCH_NUM

Açıklama

mysql_fetch_row(resource $result): array

Returns a numerical array that corresponds to the fetched row and moves the internal data pointer ahead.

Bağımsız Değişkenler

sonuç: resource türünde sorgu sonucu. Bu sonuç bir mysql_query() çağrısının sonucudur.

Dönen Değerler

Returns an numerical array of strings that corresponds to the fetched row, or false if there are no more rows.

mysql_fetch_row() fetches one row of data from the result associated with the specified result identifier. The row is returned as an array. Each result column is stored in an array offset, starting at offset 0.

Örnekler

Örnek 1 Fetching one row with mysql_fetch_row()

<?php
$result = mysql_query("SELECT id,email FROM people WHERE id = '42'");
if (!$result) {
    echo 'Could not run query: ' . mysql_error();
    exit;
}
$row = mysql_fetch_row($result);

echo $row[0]; // 42
echo $row[1]; // the email value
?>

Notlar

Bilginize: Bu işlev NULL alanlara PHP null değerini atar.

Ayrıca Bakınız

mysql_fetch_array() - Fetch a result row as an associative array, a numeric array, or both
mysql_fetch_assoc() - Fetch a result row as an associative array
mysql_fetch_object() - Fetch a result row as an object
mysql_data_seek() - Move internal result pointer
mysql_fetch_lengths() - Bir sonuçtaki her bir çıktının uzunluğunu al
mysql_result() - Get result data

add a note

User Contributed Notes 8 notes

down

-14

michael and then an at sign wassupy.com ¶

21 years ago


to print an array, simply use print_r(array name)

like this:
    $myrow = mysql_fetch_row($result);
echo "<pre>";
print_r($myrow);
echo "</pre>";

this will output the array in a readable form, with the index, too. Don't forget the 'pre' tags or the output will be on a single line.

down

-21

a at simongrant dot org ¶

22 years ago


Maybe worth pointing out that all the fields returned by this (and other?) calls are returned with type string. This had me puzzled for quite some time.

down

-27

pepik at gmail dot cz ¶

10 years ago


<?php  
  require 'prhlavicka.php'; 
  pis_hlavicku('Vypis článků');         
    
   require_once 'db.php';
    $kom = new server();
    $sql=$kom->query("SELECT autor,nazev,obsah FROM `Clanky_Sadek`");
               while ($data = mysql_fetch_row($sql)){
                 ECHO '<br />--AUTOR--<br />'.$data[0].'<br />__NÁZEV ČLÁNKU__<br />'.$data[1].'<br />..OBSAH ČLÁNKU..<br />'.$data[2];     }    
  
  include 'Paticka.html'; ?>

down

-30

larkitetto at gmail dot com ¶

16 years ago


sry :) note now fixed:

<?php
$esi=mysql_list_tables($db);$ris=mysql_fetch_row($esi);
//example: $db has >= 1 tabs
echo var_dump($ris);
//echoes only array(1). solution:
while($ris=mysql_fetch_row($esi)) echo $ris[0];
/*debug:
$ris=array("1st_tab"); ... $ris=array("n_tab");$ris=false;*/
while ($ris[]=mysql_fetch_row($esi));
//debug:$ris=array(array("1st_tab"), ... array("n_tab"));
echo $ris[n][0];//echo:"n_tab"
echo $ris[0][n];//echo:array | null
?>

hope it helps

down

-41

jhulbert at redf dot com ¶

14 years ago


Creates table from all db info:

<?php
$qry = "SELECT * FROM exp_member_data";
$res = mysql_query($mem_qry);

function mysql_fetch_all($res) {
   while($row=mysql_fetch_array($res)) {
       $return[] = $row;
   }
   return $return;
}

function create_table($dataArr) {
    echo "<tr>";
    for($j = 0; $j < count($dataArr); $j++) {
        echo "<td>".$dataArr[$j]."</td>";
    }
    echo "</tr>";
}

$all = mysql_fetch_all($res);

echo "<table class='data_table'>";

for($i = 0; $i < count($all); $i++) {
    create_table($all[$i]);
}

echo "</table>";

?>

down

-45

ryhan_balboa at yahoo dot com ¶

16 years ago


The following are the basic codes to get a specific row from the mysql db into a $row variable:

 
$query = "SELECT * FROM table"; 
$result = mysql_query($query); 
$row = mysql_fetch_row($result);

And $row[0], $row[1] ... $row[n] are used to access those field values. 

Does anyone know how I can add a new field to $row, so that the field count increases from n to n+1?

I have tried treating $row like an array, and tried array_push function, but didn't work.

Thanks.

down

-47

m dot s at programmers-online dot net ¶

18 years ago


The following function to read all data out of a mysql-resultset, is may be faster than Rafaels solution:

<?
function mysql_fetch_all($result) {
   while($row=mysql_fetch_array($result)) {
       $return[] = $row;
   }
   return $return;
}
?>

down

-49

murapaka dot sateesh at gmail dot com ¶

9 years ago


<?php

$conn=mysql_connect("localhost","root","");
if($conn)
{
    echo("Connection Successfully");
    $seldb=mysql_select_db("test",$conn);
    if($seldb)
    {
        echo("Database selected successfully");
        $retrive=mysql_query("select name,number from login1 where name='sateesh'",$conn);
        if($retrive)
        {
            echo("Successfully data retrived<br>");
            
            $result=mysql_fetch_row($retrive);
            
                echo ("Name".$result[0]);
                echo ("Number".$result[1]);
                    
        }
        else
        {
        echo "Table not inserted";
        }
        }
        else
        {
            die("database not selected");
        }
    }
    else
    {
        die("connection faild");    
    }
    mysql_close($conn);
?>

add a note