This page should include a note on variable lifecycle:
Before a variable is used, it has no existence. It is unset. It is possible to check if a variable doesn't exist by using isset(). This returns true provided the variable exists and isn't set to null. With the exception of null, the value a variable holds plays no part in determining whether a variable is set.
Setting an existing variable to null is a way of unsetting a variable. Another way is variables may be destroyed by using the unset() construct.
<?php
print isset($a); // $a is not set. Prints false. (Or more accurately prints ''.)
$b = 0; // isset($b) returns true (or more accurately '1')
$c = array(); // isset($c) returns true
$b = null; // Now isset($b) returns false;
unset($c); // Now isset($c) returns false;
?>
is_null() is an equivalent test to checking that isset() is false.
The first time that a variable is used in a scope, it's automatically created. After this isset is true. At the point at which it is created it also receives a type according to the context.
<?php
$a_bool = true; // a boolean
$a_str = 'foo'; // a string
?>
If it is used without having been given a value then it is uninitalized and it receives the default value for the type. The default values are the _empty_ values. E.g Booleans default to FALSE, integers and floats default to zero, strings to the empty string '', arrays to the empty array.
A variable can be tested for emptiness using empty();
<?php
$a = 0; //This isset, but is empty
?>
Unset variables are also empty.
<?php
empty($vessel); // returns true. Also $vessel is unset.
?>
Everything above applies to array elements too.
<?php
$item = array();
//Now isset($item) returns true. But isset($item['unicorn']) is false.
//empty($item) is true, and so is empty($item['unicorn']
$item['unicorn'] = '';
//Now isset($item['unicorn']) is true. And empty($item) is false.
//But empty($item['unicorn']) is still true;
$item['unicorn'] = 'Pink unicorn';
//isset($item['unicorn']) is still true. And empty($item) is still false.
//But now empty($item['unicorn']) is false;
?>
For arrays, this is important because accessing a non-existent array item can trigger errors; you may want to test arrays and array items for existence with isset before using them.
Basics
Variables in PHP are represented by a dollar sign followed by the name of the variable. The variable name is case-sensitive.
Variable names follow the same rules as other labels in PHP. A
valid variable name starts with a letter or underscore, followed
by any number of letters, numbers, or underscores. As a regular
expression, it would be expressed thus:
^[a-zA-Z_\x80-\xff][a-zA-Z0-9_\x80-\xff]*$
Notă: For our purposes here, a letter is a-z, A-Z, and the bytes from 128 through 255 (
0x80-0xff).
Notă:
$thisis a special variable that can't be assigned. Prior to PHP 7.1.0, indirect assignment (e.g. by using variable variables) was possible.
Sfat
Accesați de asemenea Ghidul de stabilire a denumirilor de către utilizatori.
For information on variable related functions, see the Variable Functions Reference.
<?php
$var = 'Bob';
$Var = 'Joe';
echo "$var, $Var"; // outputs "Bob, Joe"
$4site = 'not yet'; // invalid; starts with a number
$_4site = 'not yet'; // valid; starts with an underscore
$täyte = 'mansikka'; // valid; 'ä' is (Extended) ASCII 228.
?>
By default, variables are always assigned by value. That is to say, when you assign an expression to a variable, the entire value of the original expression is copied into the destination variable. This means, for instance, that after assigning one variable's value to another, changing one of those variables will have no effect on the other. For more information on this kind of assignment, see the chapter on Expressions.
PHP also offers another way to assign values to variables: assign by reference. This means that the new variable simply references (in other words, "becomes an alias for" or "points to") the original variable. Changes to the new variable affect the original, and vice versa.
To assign by reference, simply prepend an ampersand (&) to the
beginning of the variable which is being assigned (the source
variable). For instance, the following code snippet outputs 'My
name is Bob' twice:
<?php
$foo = 'Bob'; // Assign the value 'Bob' to $foo
$bar = &$foo; // Reference $foo via $bar.
$bar = "My name is $bar"; // Alter $bar...
echo $bar;
echo $foo; // $foo is altered too.
?>
One important thing to note is that only named variables may be assigned by reference.
<?php
$foo = 25;
$bar = &$foo; // This is a valid assignment.
$bar = &(24 * 7); // Invalid; references an unnamed expression.
function test()
{
return 25;
}
$bar = &test(); // Invalid.
?>
It is not necessary to initialize variables in PHP however it is a very
good practice. Uninitialized variables have a default value of their type depending on the context in which they are used
- booleans default to false, integers and floats default to zero, strings (e.g. used in echo) are
set as an empty string and arrays become to an empty array.
Example #1 Default values of uninitialized variables
<?php
// Unset AND unreferenced (no use context) variable; outputs NULL
var_dump($unset_var);
// Boolean usage; outputs 'false' (See ternary operators for more on this syntax)
echo($unset_bool ? "true\n" : "false\n");
// String usage; outputs 'string(3) "abc"'
$unset_str .= 'abc';
var_dump($unset_str);
// Integer usage; outputs 'int(25)'
$unset_int += 25; // 0 + 25 => 25
var_dump($unset_int);
// Float/double usage; outputs 'float(1.25)'
$unset_float += 1.25;
var_dump($unset_float);
// Array usage; outputs array(1) { [3]=> string(3) "def" }
$unset_arr[3] = "def"; // array() + array(3 => "def") => array(3 => "def")
var_dump($unset_arr);
// Object usage; creates new stdClass object (see http://www.php.net/manual/en/reserved.classes.php)
// Outputs: object(stdClass)#1 (1) { ["foo"]=> string(3) "bar" }
$unset_obj->foo = 'bar';
var_dump($unset_obj);
?>
Relying on the default value of an uninitialized variable is problematic in the case of including one file into another which uses the same variable name. It is also a major security risk with register_globals turned on. E_NOTICE level error is issued in case of working with uninitialized variables, however not in the case of appending elements to the uninitialized array. isset() language construct can be used to detect if a variable has been already initialized.
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User Contributed Notes 6 notes
jeff dot phpnet at tanasity dot com ¶
13 years ago
anisgazig at gmail dot com ¶
3 years ago
clear concept of variable declaration rules and classification
variable declaration rules:
1.start with dollar sign($)
2.first letter of variable name comes from a-zA-z_
3.next letters of variable name comes from a-zA-Z0-9_
4.no space,no syntex
classification of variables:
Variable are mainly Two types
1.Predefined Variable
2.User Define Variable
Predefined Variable
There are 12 predefined variables in php 8
1.$GLOBALS
2.$_SERVER
3.$_REQUEST
4.$_FILES
5.$_ENV
6.$_SESSION
7.$_COOKIE
8.$_GET
9.$_POST
10.$http_response_header
11.$argc
12.$argv
User Define Variable
User Define variable are 3 types
1.variable scope
2.variable variables
3.reference variable
Variable Scope
variable scope are 3 types
1.local scope
2.global scope
3.static variable
Anonymous ¶
7 years ago
I highly recommend to use an editor that can list all variable names in a separate window.
The reason are typing errors in variable names.
<?php
$somename = "nobody";
// Now we want to use $somename somewhere
echo $somemane ;
?>
And wonder why it doesn't print "nobody".
The reason is simple, we have a typing error in $somename and $somemane is a new variable.
In this example it might be easy to find. But if you use variables to calculate some things, you might hardly find it and ask yourself why your calculation is always wrong.
With an editor that list all variable names in a separate window such "double" variables but with wrong typing can be easily found.
BTW:
It would have been better, if the PHP language would require to use some sort of keyword to define a variable the first time.
baoquyen804 at gmail dot com ¶
6 years ago
When examining the variable name with the regular expression [a-zA-Z_ \ x7f- \ xff] [a-zA-Z0-9_ \ x7f- \ xff] this will cause an error:
<?php
$name="aa'1'";
if(!preg_match('/^[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*/',$name))
echo $name.' is not a valid PHP variable name';
else
echo $name.' is valid PHP variable name';
// output aa'1' is valid PHP variable name
//but:
$aa'1' = 10; // error syntac
?>
instead use it ^[a-zA-Z][_]?[\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*
<?php
$name="aa'1'";
if(!preg_match('/^[a-zA-Z][_]?[\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*/', $name))
echo $name.' is not a valid PHP variable name';
else
echo $name.' is valid PHP variable name';
// output aa'1' is not valid PHP variable name
?>
maurizio dot domba at pu dot t-com dot hr ¶
13 years ago
If you need to check user entered value for a proper PHP variable naming convention you need to add ^ to the above regular expression so that the regular expression should be '^[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*'.
Example
<?php
$name="20011aa";
if(!preg_match('/[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*/',$name))
echo $name.' is not a valid PHP variable name';
else
echo $name.' is valid PHP variable name';
?>
Outputs: 2011aa is valid PHP variable name
but
<?php
$name="20011aa";
if(!preg_match('/^[a-zA-Z_\x7f-\xff][a-zA-Z0-9_\x7f-\xff]*/',$name))
echo $name.' is not a valid PHP variable name';
else
echo $name.' is valid PHP variable name';
?>
Outputs: 2011aa is not a valid PHP variable name
anisgazig at gmail dot com ¶
3 years ago
$this is a special variable so we can not assign it.But Prior to PHP 7.1.0, indirect assignment such as variable variables are allowed.
$bd = "this";
$$bd = "CountryNickName";
echo $this;//allowed prior to PHP 7.1.0
but from the version of 7.1.0,it was allowed.
