apcu_cas

(PECL apcu >= 4.0.0)

apcu_casUpdates an old value with a new value

설명

bool apcu_cas ( string $key , int $old , int $new )

apcu_cas() updates an already existing integer value if the old parameter matches the currently stored value with the value of the new parameter.

인수

key

The key of the value being updated.

old

The old value (the value currently stored).

new

The new value to update to.

반환값

성공 시 TRUE를, 실패 시 FALSE를 반환합니다.

예제

Example #1 apcu_cas() example

<?php
apcu_store
('foobar'2);
echo 
'$foobar = 2'PHP_EOL;
echo 
'$foobar == 1 ? 2 : 1 = ', (apcu_cas('foobar'12) ? 'ok' 'fail'), PHP_EOL;
echo 
'$foobar == 2 ? 1 : 2 = ', (apcu_cas('foobar'21) ? 'ok' 'fail'), PHP_EOL;

echo 
'$foobar = 'apcu_fetch('foobar'), PHP_EOL;

echo 
'$f__bar == 1 ? 2 : 1 = ', (apcu_cas('f__bar'12) ? 'ok' 'fail'), PHP_EOL;

apcu_store('perfection''xyz');
echo 
'$perfection == 2 ? 1 : 2 = ', (apcu_cas('perfection'21) ? 'ok' 'epic fail'), PHP_EOL;

echo 
'$foobar = 'apcu_fetch('foobar'), PHP_EOL;
?>

위 예제의 출력 예시:

$foobar = 2
$foobar == 1 ? 2 : 1 = fail
$foobar == 2 ? 1 : 2 = ok
$foobar = 1
$f__bar == 1 ? 2 : 1 = fail
$perfection == 2 ? 1 : 2 = epic fail
$foobar = 1

참고

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User Contributed Notes 1 note

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-5
Anonymous
4 years ago
The output in the example says:

$f__bar == 1 ? 2 : 1 = fail

but in reality it should be:

$f__bar == 1 ? 2 : 1 =  ok

the first time the code is ran as the cache is empty and apcu_cas allows the key to be inserted.
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