If you are STILL getting this error, even after freeing your results:
Internal SQL Bug: 2014, Commands out of sync; you can't run this command now
You may have a stored procedure in your query. A procedure can return more than one result set, and it will always return one extra empty result set that carries some meta information on the procedure call itself, especially error information. ( source: https://bugs.mysql.com/bug.php?id=71044 )
While calling single procedures, with one SELECT in them, using mysqli->query("CALL `stored_procedure`();"), I had to do the following to make it work between two calls:
<?php
$result->free();
$mysqli->next_result();
?>
It has no negative impact if you are not calling a stored procedure.
mysqli_result::free
mysqli_result::close
mysqli_result::free_result
mysqli_free_result
(PHP 5, PHP 7, PHP 8)
mysqli_result::free -- mysqli_result::close -- mysqli_result::free_result -- mysqli_free_result — 結果に関連付けられたメモリを開放する
説明
オブジェクト指向型
手続き型
結果に関連付けられたメモリを開放します。
パラメータ
result-
手続き型のみ: mysqli_query()、mysqli_store_result()、mysqli_use_result()、mysqli_stmt_get_result() が返す mysqli_result オブジェクト。
戻り値
値を返しません。
参考
- mysqli_query() - データベース上でクエリを実行する
- mysqli_stmt_store_result() - 内部バッファに結果を保存する
- mysqli_stmt_get_result() - プリペアドステートメントから結果を mysqli_result オブジェクトとして取得する
- mysqli_store_result() - 直近のクエリから結果セットを転送する
- mysqli_use_result() - 結果セットの取得を開始する
add a note
User Contributed Notes 3 notes
jack_action100 at hotmail dot example dot com ¶
5 years ago
Vector at ionisis dot com ¶
14 years ago
If you are getting this error:
Internal SQL Bug: 2014, Commands out of sync; you can't run this command now
Then you never called mysqli_result::free(), mysqli_result::free_result(), mysqli_result::close(), or mysqli_free_result() in your script, and must call it before executing another stored procedure.
