mysqli::init
I have received many statements that the insert_id property has a bug because it "works sometimes". Keep in mind that when using the OOP approach, the actual instantiation of the mysqli class will hold the insert_id.
The following code will return nothing.
<?php
$mysqli = new mysqli('host','user','pass','db');
if ($result = $mysqli->query("INSERT INTO t (field) VALUES ('value');")) {
echo 'The ID is: '.$result->insert_id;
}
?>
This is because the insert_id property doesn't belong to the result, but rather the actual mysqli class. This would work:
<?php
$mysqli = new mysqli('host','user','pass','db');
if ($result = $mysqli->query("INSERT INTO t (field) VALUES ('value');")) {
echo 'The ID is: '.$mysqli->insert_id;
}
?>
mysqli::$insert_id
mysqli_insert_id
(PHP 5)
mysqli::$insert_id -- mysqli_insert_id — Devuelve el id autogenerado que se utilizó en la última consulta
Descripción
Estilo orientado a objetos
Estilo por procedimientos
La función mysqli_insert_id() devuelve el ID generado por una consulta en una tabla con una columna que tenga el atributo AUTO_INCREMENT. Si la última consulta no fue una sentencia INSERT o UPDATE o si la tabla modificada no tiene una columna con el atributo AUTO_INCREMENT, está función devolverá cero.
Nota:
Realizar una sentencia INTERT o UPDATE usando la función LAST_INSERT_ID() modificará el valor retornado por la función mysqli_insert_id().
Parámetros
-
link -
Sólo estilo por procediminetos: Un identificador de enlace devuelto por mysqli_connect() o mysqli_init()
Valores devueltos
El valor de el campo AUTO_INCREMENT que fué actualizado por la consulta anterior. Devuelve cero si no hubo una consulta previa en la conexión o si la consulta no actualiza un valor AUTO_INCREMENT.
Nota:
Si el número es mayor que el valor máximo int, mysqli_insert_id() retornará un string.
Ejemplos
Ejemplo #1 Ejemplo de $mysqli->insert_id
Estilo orientado a objetos
<?php
$mysqli = new mysqli("localhost", "mi_usuario", "mi_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Error de conexión: %s\n", mysqli_connect_error());
exit();
}
$mysqli->query("CREATE TABLE myCity LIKE City");
$query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";
$mysqli->query($query);
printf ("Nuevo registro con el id %d.\n", $mysqli->insert_id);
/* drop table */
$mysqli->query("DROP TABLE myCity");
/* close connection */
$mysqli->close();
?>
Estilo por procedimientos
<?php
$link = mysqli_connect("localhost", "mi_usuario", "mi_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Error de conexión: %s\n", mysqli_connect_error());
exit();
}
mysqli_query($link, "CREATE TABLE myCity LIKE City");
$query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";
mysqli_query($link, $query);
printf ("Nuevo registro con el id %d.\n", mysqli_insert_id($link));
/* drop table */
mysqli_query($link, "DROP TABLE myCity");
/* close connection */
mysqli_close($link);
?>
El resultado de los ejemplos serían:
Nuevo registro con el id 1.
add a note
User Contributed Notes
mysqli::$insert_id - [6 notes]
will at phpfever dot com ¶
7 years ago
Nick Baicoianu ¶
6 years ago
When running extended inserts on a table with an AUTO_INCREMENT field, the value of mysqli_insert_id() will equal the value of the *first* row inserted, not the last, as you might expect.
<?
//mytable has an auto_increment field
$db->query("INSERT INTO mytable (field1,field2,field3) VALUES ('val1','val2','val3'),
('val1','val2','val3'),
('val1','val2','val3')");
echo $db->insert_id; //will echo the id of the FIRST row inserted
?>
bert at nospam thinc dot nl ¶
4 years ago
Watch out for the oo-style use of $db->insert_id. When the insert_id exceeds 2^31 (2147483648) fetching the insert id renders a wrong, too large number. You better use the procedural mysqli_insert_id( $db ) instead.
[EDIT by danbrown AT php DOT net: This is another prime example of the limits of 32-bit signed integers.]
alan at commondream dot net ¶
8 years ago
I was having problems with getting the inserted id, and did a bit of testing. It ended up that if you commit a transaction before getting the last inserted id, it returns 0 every time, but if you get the last inserted id before committing the transaction, you get the correct value.
matix.bg a gmail ¶
7 years ago
Some people are wondering how to get the ids of the rows inserted with loop. Here is it:
<?php
// stmt_init ...
for (;;;) {
// do some things...
$stmt->execute();
$ids[] = $mysqli->insert_id;
}
?>
fizzyorange at gmail dot com ¶
4 years ago
Note that if you Call a MySQL stored procedure to insert a new record and then reference $db->insert_id; you will get 0 back, not the last inserted ID.
It is therefore necessary to add a line to your MySQL Stored Procedure such as
select last_insert_id() as intRecordKey;
after the insert so that the query will return the new key value.
Then in your php code you can use the following
<?php
$objInsertResult = $db->query($strSQL);
$objInsertRow = $objInsertResult->fetch_object();
$intRecordKey = $objInsertRow->intRecordKey;
?>
It would however be nice if $db->insert_id did return the last insert ID following a stored procedure call.