PHP 5.4.31 Released

session_is_registered

(PHP 4, PHP 5 < 5.4.0)

session_is_registeredAveriguar si una variable global está registrada en una sesión

Descripción

bool session_is_registered ( string $name )

Averigua si una variable global está registrada en una sesión.

Advertencia

Esta función ha sido declarada OBSOLETA desde PHP 5.3.0 y ELIMINADA a partir de PHP 5.4.0.

Parámetros

name

El nombre de la variable.

Valores devueltos

session_is_registered() devuelve TRUE si hay una variable global con el nombre name registrada en la sesión actual, FALSE si no.

Notas

Nota:

Si se usa$_SESSION (o $HTTP_SESSION_VARS para PHP 4.0.6 o anterior), utilice isset() para verificar si una variable está registrada en $_SESSION.

Precaución

Si está usando $_SESSION (o $HTTP_SESSION_VARS), no use session_register(), session_is_registered() y session_unregister().

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User Contributed Notes 7 notes

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2
paimpozhil at gmail dot com
1 year ago
For those who have an older application which uses the session_is_registered..and you want to use that in php5.4

You can just define the function if required

function session_is_registered($x)
{
    if (isset($_SESSION['$x']))
    return true;
    else
    return false;
}

May be add the checks to ensure function is not already existing..
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0
someone at the dot inter dot net
4 months ago
A simple one-line function to emulate this in later versions of PHP:
function session_is_registered($x){return isset($_SESSION['$x']);}
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-1
miguel dot simoes at swirve dot com
12 years ago
When using PHP 4.2.0 even on the same page where you registered the variable with:

session_register("someVar");

if you try to see if the variable is set and do not assign it a value before, the function used in the previous comment will give the same output.
This may show that the variable is declared and will not be set until some value is give assign to it.
I think that this way will give the option to register all the variables used for sure on the process on the first page and using them as the time comes.
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-1
someone at the dot inter dot net
4 months ago
A simple one-line function to emulate this in later versions of PHP:
function session_is_registered($x){return isset($_SESSION['$x']);}
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-3
amol_bhavsar1982 at hotmail dot com
5 years ago
session_register() function is generating warnings. Therefore, instead of using:

<?php
$test
= 'Here';
session_register('test');
?>

It is better :

<?php
$_SESSION
['test'] = 'Here';
?>
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-5
Sami
5 months ago
I can not get the following code to work as it is returning an error on the session_is_registered() and do I have to change anything else in the code

Thank you

if(!session_is_registered('user_name')){

if (isset($_POST['username'])) {
$password1 = clean($_POST["password"]);
$username1 = clean($_POST["username"]);
$password2 = crypt($password1);

$result = @mysql_query ("select * from users where user_name = '".$username1."'");
$lim = @mysql_num_rows( $result );
//|| (strlen($username1) < 6) || (strlen($password1) < 6)
if( ($lim!=0)  ){
$row = @mysql_fetch_array($result);
$password=$row['user_password'];
if (crypt($password1, $password) == $password){
$sql = @mysql_query ("insert into logs (ip, cdate, status) values ('".$REMOTE_ADDR."','". date("Y-m-d H:i:s") ."', 'Login')");
session_register('user_id');
session_register('user_fullname');
session_register('user_name');

$_SESSION['user_name'] = $row['user_name'];
$_SESSION['user_fullname'] = $row['user_fullname'];
$_SESSION['user_id'] = $row['user_id'];
}//if crypt
else{
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-9
vectorjohn at example dot com
7 months ago
The proper equivalent has nothing to do with isset().

Use array_key_exists() because session_is_registered returns true if the variable is in the session at all, even if it's falsy.
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