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ftp_site

(PHP 4, PHP 5)

ftp_siteEnvía un comando SITE al servidor

Descripción

bool ftp_site ( resource $ftp_stream , string $command )

ftp_site() envía el comando SITE especificado al servidor FTP.

Los comandos SITE no están estandarizados, y varían de un servidor a otro. Son útiles para la gestión de cosas como los permisos de archivos y la membresía de grupos.

Parámetros

ftp_stream

El identificador de enlace de la conexión FTP.

command

El comando SITE. Tenga en cuenta que este parámetro no es escapado, lo que puede provocar algunos problemas con nombres de archivos que contengan espacios y otros caracteres.

Valores devueltos

Devuelve TRUE en caso de éxito o FALSE en caso de error.

Ejemplos

Ejemplo #1 Envío de un comando SITE a un servidor FTP

<?php
// Conectar con el servidor FTP
$conn ftp_connect('ftp.example.com');
if (!
$conn) die('No se puede conectar al servidor ftp.example.com');

// Iniciar sesion como "user" con la contraseña "pass"
if (!ftp_login($conn'user''pass')) die('Error al iniciar sesión en ftp.example.com');

// Aplicar el comando: "SITE CHMOD 0600 /home/user/privatefile" al servidor ftp
if (ftp_site($conn'CHMOD 0600 /home/user/privatefile')) {
   echo 
"Comando ejecutado con éxito.\n";
} else {
   die(
'El comando ha fallado.');
}
?>

Ver también

  • ftp_raw() - Envía un comando arbitrario a un servidor FTP

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User Contributed Notes 6 notes

up
1
Marc
11 years ago
Use ftp_raw() (PHP 5+) instead of ftp_site() if you need the results of the remote command.
up
1
to at mail dot isec dot pt
11 years ago
Hya,
  Recently I had to work with FTP over PHP, since I didn't found any help about this topic I decided to post this here. If you need to chmod one file, I tested this on the ftp server using a ftp client and after I knew that the ftp server supported chmod I used the following commands:
$upload = ftp_put($conn_id, "/home/to/public_html/index.php", $source_file, FTP_ASCII);
$ch=@ftp_site($conn_id,"chmod 755 /home/to/public_html/index.php");

Hope this help!

T
up
1
Anonymous
13 years ago
site commands are extra-functionality provided by some ftp servers, and depend on the server :
e.g. trying "ftp> site help" (with an interactive ftp client) on a proftp server would give :

214-The following SITE extensions are recognized:
RATIO -- show all ratios in effect
The following SITE commands are recognized (* =>'s unimplemented).
HELP    CHMOD
214 Direct comments to admin@ftp.blahblah.fr

while with wu-ftpd on can typically get :

214-The following SITE commands are recognized (* =>'s unimplemented).
   UMASK           GROUP           INDEX           GROUPS
   IDLE            GPASS           EXEC            CHECKMETHOD
   CHMOD           NEWER           ALIAS           CHECKSUM
   HELP            MINFO           CDPATH                  
214 blabla

Unfortunately, ftp_site only returns true or false. It would be nice to have a way to get the server's reply in full : ftp_site('help') return 1, which pretty much useless.

Hope that helps,

Ivan
up
0
www.bossftp.com
5 years ago
To send a SITE command and get the result, you can try this:

<?php
function ftpsite($conn, $cmd) {
    return
ftp_raw($conn, "SITE $cmd");
}
?>
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0
webmaster at beezm dot net
11 years ago
I wrote some functions for an ftp server for windows called GuildFTPd.

Here they are, they are pretty much so self explanitory:
<?
function guildftpd_adduser($ftp_stream,$group,$username,$password){
   
ftp_site($ftp_stream,"SITE ADDUSER $group $username $password");
}
function
guildftpd_addgroup($ftp_stream,$groupname){
   
ftp_site($ftp_stream,"SITE ADDGROUP $groupname");
}
function
guildftpd_deluser($ftp_stream,$username){
   
ftp_site($ftp_stream,"SITE DELUSER $username");
}
function
guildftpd_addpath($ftp_stream,$username,$path,$vpath){
   
ftp_site($ftp_stream,"SITE ADDPATH $username $path $vpath");
}
function
guildftpd_delpath($ftp_stream,$username,$path,$vpath){
   
ftp_site($ftp_stream,"SITE DELPATH $username $path $vpath");
}
function
guildftpd_anon($ftp_stream){
   
ftp_site($ftp_stream,"SITE ANON ALLOW");
}
function
guildftpd_anond($ftp_stream){
   
ftp_site($ftp_stream,"SITE ANON DENY");
}
function
guildftpd_chpass($ftp_stream,$user,$pass){
   
ftp_site($ftp_stream,"SITE CHPASS $user $pass");
}
function
guildftpd_disable($ftp_stream,$user){
   
ftp_site($ftp_stream,"SITE DISABLE $user");
}
function
guildftpd_enable($ftp_stream,$user){
   
ftp_site($ftp_stream,"SITE ENABLE $user");
}
function
guildftpd_who($ftp_stream){
   
$who = ftp_site($ftp_stream,"SITE WHO");
}
function
guildftpd_kick($ftp_stream,$user);
   
ftp_site($ftp_stream,"SITE KICK $user");
}
function
guildftpd_msg($ftp_stream,$text);
   
ftp_site($ftp_stream,"SITE MSG $text");
}
?>
up
0
daemorhedron
11 years ago
I'd like to follow up with Ivan's observation there. Unless I am missing the obvious, which is entirely possible of course, this command is quite useless unless it returns the data from the SITE <foo> request.

Besides the obvious SITE HELP command, another one that would require catching the feedback would be the SITE LOCATE | SITE SEARCH commands. I completely recognize that SITE <foo> commands are indeed insanely proprietary, but the fact still remains that changing this to return the results, or at least having the option to do so (such as exec() and the like) would be vastly preferred to the current method of returning true/false values.

Thanks.
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