basename

(PHP 4, PHP 5, PHP 7, PHP 8)

basenameDevuelve el último componente de nombre de una ruta

Descripción

basename(string $path, string $suffix = ?): string

Dada una cadena que contiene una ruta a un archivo o directorio, esta función devolverá el último componente de nombre.

Nota:

basename() opera nativamente en la entrada de cadena, y no es consciente del actual sistema de archivos, o componentes de ruta como "..".

Precaución

basename() es consciente de su sistema de localidad, así que para ver el nombre base correcto con rutas de caracteres multibyte, la localidad debe coincidir con la establecida con la función setlocale().

Parámetros

path

Una ruta.

En Windows, la barra (/) y la barra invertida (\) se usan como carácter separador de directorio. En otros entornos se usa la barra hacia delante (/).

suffix

Si el nombre del componente termina en suffix éste será recortado también.

Valores devueltos

Devuelve el nombre base de path.

Ejemplos

Ejemplo #1 Ejemplo de basename()

<?php
echo "1) ".basename("/etc/sudoers.d", ".d").PHP_EOL;
echo
"2) ".basename("/etc/sudoers.d").PHP_EOL;
echo
"3) ".basename("/etc/passwd").PHP_EOL;
echo
"4) ".basename("/etc/").PHP_EOL;
echo
"5) ".basename(".").PHP_EOL;
echo
"6) ".basename("/");
?>

El resultado del ejemplo sería:

1) sudoers
2) sudoers.d
3) passwd
4) etc
5) .
6)

Ver también

  • dirname() - Devuelve la ruta de un directorio padre
  • pathinfo() - Devuelve información acerca de la ruta de un fichero

add a note add a note

User Contributed Notes 30 notes

up
30
Anonymous
6 years ago
It's a shame, that for a 20 years of development we don't have mb_basename() yet!

// works both in windows and unix
function mb_basename($path) {
    if (preg_match('@^.*[\\\\/]([^\\\\/]+)$@s', $path, $matches)) {
        return $matches[1];
    } else if (preg_match('@^([^\\\\/]+)$@s', $path, $matches)) {
        return $matches[1];
    }
    return '';
}
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31
stephane dot fidanza at gmail dot com
16 years ago
Support of the $suffix parameter has changed between PHP4 and PHP5:
in PHP4, $suffix is removed first, and then the core basename is applied.
conversely, in PHP5, $suffix is removed AFTER applying core basename.

Example:
<?php
  $file
= "path/to/file.xml#xpointer(/Texture)";
  echo
basename($file, ".xml#xpointer(/Texture)");
?>

Result in PHP4: file
Result in PHP5: Texture)
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10
(remove) dot nasretdinov at (remove) dot gmail dot com
15 years ago
There is only one variant that works in my case for my Russian UTF-8 letters:

<?php
function mb_basename($file)
{
    return
end(explode('/',$file));
}
><

It is intented for UNIX servers
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8
lazy lester
18 years ago
If your path has a query string appended, and if the query string contains a "/" character, then the suggestions for extracting the filename offered below don't work.

For instance if the path is like this:
http://www.ex.com/getdat.php?dep=n/a&title=boss

Then both the php basename() function, and also
the $_SERVER[QUERY_STRING] variables get confused.

In such a case, use:

<php
$path_with_query="http://www.ex.com/getdat.php?dep=n/a&title=boss";
$path=explode("?",$path_with_query);
$filename=basename($path[0]);
$query=$path[1];
?>
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5
zandor_zz at yahoo dot it
15 years ago
It might be useful to have a version of the function basename working with arrays too.

<?php
function a_basename( $file, $exts )
{
   
$onlyfilename = end( explode( "/", $file ) );

    if(
is_string( $exts ) )
    {
        if (
strpos( $onlyfilename, $exts, 0 ) !== false )
       
$onlyfilename = str_replace( $exts, "", $onlyfilename );
    }
    else if (
is_array( $exts ) )
    {
       
// works with PHP version <= 5.x.x
       
foreach( $exts as $KEY => $ext )
        {
           
$onlyfilename = str_replace( $ext, "", $onlyfilename );
        }
    }

    return
$onlyfilename ;
}
?>
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6
swedish boy
14 years ago
Here is a quick way of fetching only the filename (without extension) regardless of what suffix the file has.

<?php

// your file
$file = 'image.jpg';

$info = pathinfo($file);
$file_name basename($file,'.'.$info['extension']);

echo
$file_name; // outputs 'image'

?>
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1
pvollma at pcvsoftware dot net
18 years ago
There is a real problem when using this function on *nix servers, since it does not handle Windows paths (using the \ as a separator). Why would this be an issue on *nix servers? What if you need to handle file uploads from MS IE? In fact, the manual section "Handling file uploads" uses basename() in an example, but this will NOT extract the file name from a Windows path such as C:\My Documents\My Name\filename.ext. After much frustrated coding, here is how I handled it (might not be the best, but it works):

<?php
$newfile
= basename($filen);
if (
strpos($newfile,'\\') !== false) {
 
$tmp = preg_split("[\\\]",$newfile);
 
$newfile = $tmp[count($tmp) - 1];
}
?>

$newfile will now contain only the file name and extension, even if the POSTed file name included a full Windows path.
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1
KOmaSHOOTER at gmx dot de
19 years ago
If you want the current path where youre file is and not the full path then use this :)

<?php
echo('dir = '.basename (dirname($_SERVER['PHP_SELF']),"/"));   
// retuns the name of current used directory
?>

Example:

www dir: domain.com/temp/2005/january/t1.php

<?php
echo('dirname <br>'.dirname($_SERVER['PHP_SELF']).'<br><br>');   
// returns: /temp/2005/january
?>

<?php
echo('file = '.basename ($PHP_SELF,".php"));   
// returns: t1
?>

if you combine these two you get this
<?php
echo('dir = '.basename (dirname($_SERVER['PHP_SELF']),"/"));   
// returns: january
?>

And for the full path use this
<?php
echo(' PHP_SELF <br>'.$_SERVER['PHP_SELF'].'<br><br>');
// returns: /temp/2005/january/t1.php   
?>
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-1
Anonymous
7 years ago
There is a problem reading non-Latin characters in the file name if the locale is not configured correctly.
For example: instead of the name «ФЫВА-1234.doc», is displayed «-1234.doc».
Solution: rawurldecode(basename($full_name)).
up
0
KOmaSHOOTER at gmx dot de
20 years ago
Exmaple for exploding ;) the filename to an array

<?php
echo(basename ($PHP_SELF)."<br>");  // returnes filename.php
$file = basename ($PHP_SELF);
$file = explode(".",$file);
print_r($file);    // returnes Array ( [0] => filename [1] => php )
echo("<br>");
$filename = basename(strval($file[0]),$file[1]);
echo(
$filename."<br>");  // returnes  filename
echo(basename ($PHP_SELF,".php")."<br>");  // returnes  filename
echo("<br>");
echo(
"<br>");
//show_source(basename ($PHP_SELF,".php").".php")
show_source($file[0].".".$file[1])
?>
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-3
crash at subsection dot org dot uk
18 years ago
A simple way to return the current directory:
$cur_dir = basename(dirname($_SERVER[PHP_SELF]))

since basename always treats a path as a path to a file, e.g.

/var/www/site/foo/ indicates /var/www/site as the path to file
foo
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-2
amitabh at NOSPAM dot saysnetsoft dot com
18 years ago
The previous example posted by "pvollma" didn't work out for me, so I modified it slightly:
<?php
function GetFileName($file_name)
{
       
$newfile = basename($file_name);
        if (
strpos($newfile,'\\') !== false)
        {
               
$tmp = preg_split("[\\\]",$newfile);
               
$newfile = $tmp[count($tmp) - 1];
                return(
$newfile);
        }
        else
        {
                return(
$file_name);
        }
}
?>
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-3
poop at poop dot com
9 years ago
@ lcvalentine at gmail dot com
>This is much simpler:
>$ext = strrchr( $filename, '.' );

Even though yours is shorter, you can also do:

$ext = end(explode(".", basename($file
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-1
stocki dot r at gmail dot com
4 years ago
Additional note to Anonymous's mb_basename() solution: get rid of trailing slashes/backslashes!

<?php
function mb_basename($path) {
    if (
preg_match('@^.*[\\\\/]([^\\\\/]+)([\\\\/]+)?$@s', $path, $matches)) {
        return
$matches[1];
    } else if (
preg_match('@^([^\\\\/]+)([\\\\/]+)?$@s', $path, $matches)) {
        return
$matches[1];
    }
    return
'';
}

echo
mb_basename("/etc//"); # "etc"
?>
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-3
hello at haroonahmad dot co dot uk
15 years ago
I got a blank output from this code

$cur_dir = basename(dirname($_SERVER[PHP_SELF]))

suggested earlier by a friend here.

So anybody who wants to get the current directory path can use another technique that I use as

//suppose you're using this in pageitself.php page

$current_dir=dirname(realpath("pageitself.php"));

I hope it helps.
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-5
pai dot ravi at yahoo dot com
15 years ago
once you have extracted the basename from the full path and want to separate the extension from the file name, the following function will do it efficiently:

<?php
function splitFilename($filename)
{
   
$pos = strrpos($filename, '.');
    if (
$pos === false)
    {
// dot is not found in the filename
       
return array($filename, ''); // no extension
   
}
    else
    {
       
$basename = substr($filename, 0, $pos);
       
$extension = substr($filename, $pos+1);
        return array(
$basename, $extension);
    }
}
?>
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-6
lcvalentine at gmail dot com
9 years ago
@softontherocks at gmail dot com
> If you want to get the extension of a file, I posted a function in
> http://softontherocks.blogspot.com/2013/07/obtener-la-extension-de-un-fichero-con.html
>
> The function is:
>
> function getExtension($file) {
>   $pos = strrpos($file, '.');
>   return substr($file, $pos+1);
> }

This is much simpler:
$ext = strrchr( $filename, '.' );
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-7
adrian at foeder dot de
16 years ago
On windows systems, filenames are case-insensitive. If you have to make sure the right case is used when you port your application to an unix system, you may use a combination of the following:

<?php
//assume the real filename is mytest.JPG:

$name_i_have = "mytest.jpg";
$realfilename = basename(realpath($name_i_have));
?>

basename itself does not check the filesystem for the given file, it does, so it seems, only string-manipulation.
With realpath() you can "extend" this functionality.
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-6
icewind
18 years ago
Because of filename() gets "file.php?var=foo", i use explode in addition to basename like here:

$file = "path/file.php?var=foo";
$file = explode("?", basename($file));
$file = $file[0];
$query = $file[1];

Now $file only contains "file.php" and $query contains the query-string (in this case "var=foo").
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-6
Muhammad El-Saeed muhammad at elsaeed dot info
10 years ago
to get the base url of my website

function url(){
    $base_url = isset($_SERVER['HTTPS']) && strtolower($_SERVER['HTTPS']) !== 'off' ? 'https' : 'http';
    $base_url .= '://'. $_SERVER['HTTP_HOST'];
    $base_url .= str_replace(basename($_SERVER['SCRIPT_NAME']), '', $_SERVER['SCRIPT_NAME']); 
    return $base_url;
}
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-8
thoughts at highermind dot org
17 years ago
Basename without query string:

<?php
$filename   
= array_shift(explode('?', basename($url_path)));
?>
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-7
www.turigeza.com
18 years ago
simple but not said in the above examples

echo basename('somewhere.com/filename.php?id=2', '.php');
will output
filename.php?id=2

which is not the filename in case you expect!
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-6
Anonymous
18 years ago
icewinds exmaple wouldn't work, the query part would contain the second char of the filename, not the query part of the url.
<?
$file = "path/file.php?var=foo";
$file = explode("?", basename($file));
$query = $file[1];
$file = $file[0];
?>

That works better.
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-5
Anonymous
9 years ago
As already pointed out above, if a query string contains a '/' character, basename will not handle it well. But it can come really handy when you want to pass a url with query string to a funtion that copies/downloads the file using basename as local filename, by attaching  an extra query to the end of the url:

<?php
  $url
= 'http://example.com/url?with=query_string';
 
basename($url); // url?with=query_string
 
$url = $url . '&filename_for_basename=/desired_filename.ext';
 
basename($url); // desired_filename.ext
?>

Note: you can use the filename from the HTTP header (if present) to get the file with it's original filename.
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-6
daijoubu_NOSP at M_videotron dot ca
20 years ago
An faster alternative to:

<?php
array_pop
(explode('.', $fpath));
?>

would be:

<?php
substr
($fpath, strrpos($fpath, '.')); // returns the dot
?>

If you don't want the dot, simply adds 1 to the position

<?php
substr
($fpath, strrpos($fpath, '.') + 1); // returns the ext only
?>
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-7
wibgates dot kenneth at gmail dot com
6 years ago
the best way to get the filename from url is here
<?php
     
// url : http://php.net/manual/add-note.php

      
defined('baseUrlFileName') or define('baseUrlFileName',
      
explode('.',explode('/',$_SERVER['PHP_SELF'])[3])[0]);

     echo
baseUrlFileName ; // result 1

?>

Result 1 :
    add-note
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-9
softontherocks at gmail dot com
9 years ago
If you want to get the extension of a file, I posted a function in http://softontherocks.blogspot.com/2013/07/obtener-la-extension-de-un-fichero-con.html

The function is:

function getExtension($file) {
  $pos = strrpos($file, '.');
  return substr($file, $pos+1);
}
up
-5
gandung at ppp dot cylab dot cmu dot edu
7 years ago
My opinion is, remove the $suffix first, and then apply splitting the core basename ( PHP 4 ):

/*
* From stephane.fidanza@gmail.com:
*
* PHP 4: $suffix is removed first, and then the core basename is applied.
* PHP 5: $suffix is removed after applying the core basename.
*
* (c) Paulus Gandung Prakosa (rvn.plvhx@gmail.com)
*/
if ( !function_exists('php4_backward_compat_basename') )
{
        function php4_backward_compat_basename($path, $suffix = '')
        {
                if ( $suffix !== '' ) {
                        $fixed_path = substr($path, 0, strlen($path) - strlen($suffix));
                        $fixed_basename = explode('/', $fixed_path);
                }

                return ( isset($fixed_basename) ? array_pop($fixed_basename) : array_pop(explode('/', $path)) );
        }
}
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-10
KOmaSHOOTER at gmx dot de
19 years ago
if you want the name of the parent directory
<?php
$_parenDir_path
= join(array_slice(split( "/" ,dirname($_SERVER['PHP_SELF'])),0,-1),"/").'/'; // returns the full path to the parent dir
$_parenDir basename ($_parenDir_path,"/"); // returns only the name of the parent dir
// or
$_parenDir2 = array_pop(array_slice(split( "/" ,dirname($_SERVER['PHP_SELF'])),0,-1)); // returns also only the name of the parent dir
echo('$_parenDir_path  = '.$_parenDir_path.'<br>');
echo(
'$_parenDir  = '.$_parenDir.'<br>');
echo(
'$_parenDir2  = '.$_parenDir2.'<br>');
?>
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-10
frank1982
6 years ago
Try Long Path Tool as it can remove any problems that you might have.
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