PHP 5.6.29 Released

ReflectionClass::hasMethod

(PHP 5 >= 5.1.0, PHP 7)

ReflectionClass::hasMethodChecks if method is defined

Description

public bool ReflectionClass::hasMethod ( string $name )

Checks whether a specific method is defined in a class.

Parameters

name

Name of the method being checked for.

Return Values

TRUE if it has the method, otherwise FALSE

Examples

Example #1 ReflectionClass::hasMethod() example

<?php
Class {
    public function 
publicFoo() {
        return 
true;
    }

    protected function 
protectedFoo() {
        return 
true;
    }

    private function 
privateFoo() {
        return 
true;
    }

    static function 
staticFoo() {
        return 
true;
    }
}

$rc = new ReflectionClass("C");

var_dump($rc->hasMethod('publicFoo'));

var_dump($rc->hasMethod('protectedFoo'));

var_dump($rc->hasMethod('privateFoo'));

var_dump($rc->hasMethod('staticFoo'));

// C should not have method bar
var_dump($rc->hasMethod('bar'));

// Method names are case insensitive
var_dump($rc->hasMethod('PUBLICfOO'));
?>

The above example will output:

bool(true)
bool(true)
bool(true)
bool(true)
bool(false)
bool(true)

See Also

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User Contributed Notes 4 notes

up
1
phoenix at todofixthis dot com
6 years ago
Parent methods (regardless of visibility) are also available to a ReflectionObject.  E.g.,

<?php
class ParentObject {
  public function
parentPublic(  ) {
  }

  private function
parentPrivate(  ) {
  }
}

class
ChildObject extends ParentObject {
}

$Instance = new ChildObject();
$Reflector = new ReflectionObject($Instance);

var_dump($Reflector->hasMethod('parentPublic'));  // true
var_dump($Reflector->hasMethod('parentPrivate')); // true
?>
up
1
hanguofeng at gmail dot com
6 years ago
note that even if private method will also be 'has'.
up
0
flancer64 at gmail dot com
4 months ago
Annotated methods that are implemented using PHP magic methods are not recognized  by "hasMethod".

<?php
/**
* @method void annotatedMethod()
*/
class SomeClass
{
    public function
__call($name, $arguments)
    {
        echo
"this is magic method: $name.\n";
    }

    public function
codedMethod()
    {
        echo
"this is coded method.\n";
    }
}

$obj = new \SomeClass();
$obj->codedMethod();
$obj->annotatedMethod();

$ref = new ReflectionClass(\SomeClass::class);
echo
"SomeClass has 'codedMethod': " . json_encode($ref->hasMethod('codedMethod')) . ".\n";
echo
"SomeClass has 'annotatedMethod': " . json_encode($ref->hasMethod('annotatedMethod')) . ".\n";
?>

Output:

this is coded method.
this is magic method: annotatedMethod.
SomeClass has 'codedMethod': true.
SomeClass has 'annotatedMethod': false.
up
-1
michaelgranados at gmail dot com
4 years ago
A way to check if you can call an method over a class:

<?php
function is_public_method(
       
/* string */$className,
       
/* string */$method
){
   
$classInstance = new ReflectionClass($className);
    if (
$classInstance->hasMethod($method)) {
        return
false;
    }
   
$methodInstance = $instance->getMethod($method);
    return
$methodInstance->isPublic();
}
?>
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