jddayofweek

(PHP 4, PHP 5, PHP 7)

jddayofweekReturns the day of the week

Description

mixed jddayofweek ( int $julianday [, int $mode = CAL_DOW_DAYNO ] )

Returns the day of the week. Can return a string or an integer depending on the mode.

Parameters

julianday

A julian day number as integer

mode
Calendar week modes
Mode Meaning
0 (Default) Return the day number as an int (0=Sunday, 1=Monday, etc)
1 Returns string containing the day of week (English-Gregorian)
2 Return a string containing the abbreviated day of week (English-Gregorian)

Return Values

The gregorian weekday as either an integer or string.

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User Contributed Notes 4 notes

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0
kevind at communitycolor dot com
25 days ago
You need to check to see how your client wants to represent the day of week. This function returns 0 for Sundays. ISO 8601 uses 7 for Sundays.

BTW, You can also calculate the day of week with modular division:

$dow = (1 + $julianday) % 7; // returns 0 for Sundays.
$dow = ($julianday % 7) + 1; // returns 7 for Sundays.

https://en.wikipedia.org/wiki/Julian_day#Finding_day_of_week_given_Julian_day_number

To make matters confusing. The Julian Date starts at noon UTC. Some programs such as SQLITE3 use real numbers to record date and time. If you pass this function a float; it will return a different day of week for the morning than for the afternoon.

When given a julianday with a decimal part you will need to add a half day and may need further adjustment for your timezone.
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-2
alex a khimich d org
1 year ago
In my case i had lots of head pain with returning day number using this function.
Here is bypass solution using just date():

<?php
$first_day_of_September
=date('w', strtotime('1-09-2015')); // 2
?>
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-2
php at xtramicro dot com
12 years ago
Be aware that date() and mktime() only work as long as you move within the UNIX era (1970 - 2038 / 0x0 - 0x7FFFFFFF in seconds). Outside that era those functions are only generating errors.

In other words: mktime(0, 0, 0, 12, 31, 1969) *DOES NOT* work (and so doesn't date() fed with with mktime()'s result from above). But cal_to_jd(CAL_GREGORIAN, 12, 11, 1969) *DOES WORK*.

And please note that the calendar-extension's functions arguments follow the US date order: month - day - year.
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-11
nrkkalyan at rediffmail dot com
12 years ago
You can get todays day time and date using this code

<?php
echo date("d")." ";
echo
date("m")." ";
echo
date("Y")." ";
echo
date("h:i:s A");

ECHO
' <br/>';
echo
jddayofweek ( cal_to_jd(CAL_GREGORIAN, date("m"),date("d"), date("Y")) , 1 );
?>
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