easter_date

(PHP 4, PHP 5)

easter_date Zeitpunkt des Osterfestes (0 Uhr) als Unix-Timestamp

Beschreibung

int easter_date ([ int $year ] )

Diese Funktion liefert den Unix-Timestamp (in Sekunden seit 1970) zurück, der dem Begin des Ostersonntag im durch year spezifizierten Jahr entspricht.

Warnung

Liegt das angegebene Jahr vor 1970 oder nach 2037 (auf 32 bit-Systemen), so wird eine Warnung ausgegeben und das Ergebnis ist nicht gültig.

Das Datum des Osterfestes wurde im Jahre 325 auf dem Konzil von Nicaea auf den ersten Sonntag nach Frühlingsvollmond, also dem Vollmond während oder direkt nach der Tagundnachtgleiche am 21. März, festgelegt. Der hier genutzte Algorithmus wurde um das Jahr 532 von Dionysius Exiguus eingeführt. Bis zum Jahr 1752 wird nach dem Julianischen Kalender ein einfacher 19jähriger Zyklus für die Bestimmung der Mondphasen benutzt. Im September 1752 übernahmen dann auch Britannien und seine Kolonien den von Clavius und Lilius vorgeschlagenen und im Oktober 1582 von Papst Gregor dem XIII. eingeführten Gregorianischen Kalender. Hierdurch wurden zwei Korrekturfaktoren eingeführt, um den Zyklus genauer abzubilden.

Parameter-Liste

year

Das Jahr als Zahl zwischen 1970 und 2037

Rückgabewerte

Das Osterdatum als Unix Timestamp.

Changelog

Version Beschreibung
Seit 4.3.0 Der Parameter year ist nun optional und wird mit dem aktuellen Jahr entsprechend der lokalen Zeit vorbelegt wenn nicht angegeben.

Beispiele

Beispiel #1 easter_date() Beispiel

<?php

echo date("M-d-Y"easter_date(1999));        // Apr-04-1999
echo date("M-d-Y"easter_date(2000));        // Apr-23-2000
echo date("M-d-Y"easter_date(2001));        // Apr-15-2001

?>

Siehe auch

  • easter_days() - Anzahl der Tage zwischen dem 21. März und Ostersonntag zur Berechnung des Osterdatums vor 1970 oder nach 2037

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User Contributed Notes 9 notes

up
3
py dot lebecq at gmail dot com
4 years ago
I recently had to write a function that allows me to know if today is a holiday.

And in France, we have some holidays which depends on the easter date. Maybe this will be helpful to someone.

Just modify in the $holidays array the actual holidays dates of your country.

<?php
/**
* This function returns an array of timestamp corresponding to french holidays
*/
protected static function getHolidays($year = null)
{
  if (
$year === null)
  {
   
$year = intval(date('Y'));
  }
   
 
$easterDate  = easter_date($year);
 
$easterDay   = date('j', $easterDate);
 
$easterMonth = date('n', $easterDate);
 
$easterYear   = date('Y', $easterDate);

 
$holidays = array(
   
// These days have a fixed date
   
mktime(0, 0, 0, 11$year),  // 1er janvier
   
mktime(0, 0, 0, 51$year),  // Fête du travail
   
mktime(0, 0, 0, 58$year),  // Victoire des alliés
   
mktime(0, 0, 0, 714, $year),  // Fête nationale
   
mktime(0, 0, 0, 815, $year),  // Assomption
   
mktime(0, 0, 0, 11, 1$year),  // Toussaint
   
mktime(0, 0, 0, 11, 11, $year),  // Armistice
   
mktime(0, 0, 0, 12, 25, $year),  // Noel

    // These days have a date depending on easter
   
mktime(0, 0, 0, $easterMonth, $easterDay + 2$easterYear),
   
mktime(0, 0, 0, $easterMonth, $easterDay + 40, $easterYear),
   
mktime(0, 0, 0, $easterMonth, $easterDay + 50, $easterYear),
  );

 
sort($holidays);
 
  return
$holidays;
}
?>
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2
maxie
6 years ago
To compute the correct Easter date for Eastern Orthodox Churches I made a function based on the Meeus Julian algorithm:

<?php
function orthodox_eastern($year) {
   
$a = $year % 4;
   
$b = $year % 7;
   
$c = $year % 19;
   
$d = (19 * $c + 15) % 30;
   
$e = (2 * $a + 4 * $b - $d + 34) % 7;
   
$month = floor(($d + $e + 114) / 31);
   
$day = (($d + $e + 114) % 31) + 1;
   
   
$de = mktime(0, 0, 0, $month, $day + 13, $year);
   
    return
$de;
}
?>
up
1
Guillaume Dufrene
1 year ago
I found a problem with holidays timestamp computation and daylight saving time.
An article about it at http://goo.gl/76t31 (in french only, sorry).

In summary, this year (2013) easter begins before adding an hour for daylight saving time (occured sunday at 3:00). It means that if you do $easter + X, where x is a number of seconds equivalent to one day, 39 days or 50 days, the result is not equals to a midnight timestamp...

Here a function to check if a midnight timestamp is equals to an holiday :

function isHoliday( $ts ) {
// Licence : Creative Commons (BY)
// By Webpulser - http://goo.gl/76t31
  $fixed_holidays = array( ’01-01′, ’01-05′, ’08-05′, ’14-07′, ’15-08′, ’11-11′, ’25-12′ );
  $format = ‘d-m’;

$dm = date($format, $ts);
  if ( in_array($dm, $fixed_holidays) ) return true;

$easter = easter_date( date(‘Y’, $ts) );
  if ( date($format, $easter +   86400) == $dm ) return true;
  if ( date($format, $easter + 3369600) == $dm ) return true;
  if ( date($format, $easter + 4320000) == $dm ) return true;

return false;
}

feel free to use / modify.
up
0
adwil at live dot com
6 months ago
Hey, recently I needed a function to get realization dates in online shop, so here it is (ready to go for polish users, please adjust your dates for any other country):

<?php
function getWorkday($date1,$workDays) {
       
$workDays = (int)$workDays;
        if (
$workDays <= 0)
            return
null;

       
$date1=strtotime('-1 day',strtotime($date1));

       
$lastYear = null;
       
$hol=array('01-01','01-06','05-01','05-03','08-15','11-01','11-11','12-25','12-26');  //array of month-date of static holidays (these are from Poland)
       
$i = 0;
        while (
$i<=$workDays) {
           
$year = date('Y', $date1);
            if (
$year !== $lastYear){
               
$lastYear = $year;
               
$easter = date('m-d', easter_date($year));
               
$date = strtotime($year . '-' . $easter); // easter
               
$easterSec = date('m-d', strtotime('+1 day', $date)); // easter monday
               
$greens = date('m-d', strtotime('+49 days', $date)); // zielone swiatki
               
$cc = date('m-d', strtotime('+60 days', $date)); // boze cialo
               
$hol[] = $easter;
               
$hol[] = $easterSec;
               
$hol[] = $greens;
               
$hol[] = $cc;
            }
           
$weekDay=date('w',$date1);
            if (!(
$weekDay==0 || $weekDay==6 || in_array(date('m-d',$date1),$hol)))
               
$i++;

           
$date1=strtotime('+1 day',$date1);
        }
        return
date('Y-m-d',$date1);
    }
?>
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0
peter dot burden at gmail dot com
4 years ago
In 5.3.1 easter_date() returns GMT of start of Easter Day in UK allowing
for UK Summer Time. If you are in another time zone you need to
calculate offsets.
<?php
        $e1
= easter_date(2008);
       
$e2 = easter_date(2009);
        echo
"Timestamps " . $e1 . " " . $e2 . "\n";

       
//      Timestamps 1206230400 1239490800

       
echo "Days between Easter 2008 Easter 2009 = " . ($e2-$e1)/86400 . "\n";

       
//      Days between Easter 2008 Easter 2009 = 384.958333333 - i.e. 384 days 23 hours

       
date_default_timezone_set("Europe/London");
        echo
date( " l, jS F Y H:i TO",$e1) . "\n";
        echo
date( " l, jS F Y H:i TO",$e2) . "\n";

       
//      Sunday, 23rd March 2008 00:00 GMT+0000
        //      Sunday, 12th April 2009 00:00 BST+0100

       
date_default_timezone_set("America/New_York");
        echo
date( " l, jS F Y H:i TO",$e1) . "\n";
        echo
date( " l, jS F Y H:i TO",$e2) . "\n";

       
//      Saturday, 22nd March 2008 20:00 EDT-0400
        //      Saturday, 11th April 2009 19:00 EDT-0400
        //      Daylight saving time in effect - New York 4 hours behind GMT
?>
up
0
nigelf at esp dot co dot uk
6 years ago
v5.2.1 - There is a known bug with easter_date() that can return incorrect dates for some years:

<?php
// 2008 OK
echo date("D d M Y", easter_date(2008));  // Sun 23 Mar 2008

// 2009 returns Saturday
echo date("D d M Y", easter_date(2009));  // Sat 11 Apr 2009
?>


However easter_days() works correctly:

<?php
echo date("D d M Y", strtotime("2009-03-21 +".easter_days(2009)." days"));  // Sun 12 Apr 2009
?>

It is apparently related to timezone settings.
up
0
Anonymous
8 years ago
I made the function like this ... works fine !

<?php
function ostern
{
   
$maerz21=date('z',mktime(0,0,0,3,21,$jb));

   
$d=((15 + $jb/100 - $jb/400 - (8 * $jb/100 + 13) / 25)%30 + 19 * ($jb%19))%30;

    if (
$d==29)
    {
       
$D=28;
    }
    elseif(
$d==28 && ($jb%17)>=11)
    {
       
$D=27;
    }
    else
$D=$d;   

   
$e=(2 * ($jb%4) + 4 *($jb%7) + 6 * $D + (6 + $jb/100 - $jb/400 - 2)%7)%7;

   
$ostersonntag=$e+$D+1+$maerz21;
    return
$ostersonntag;
}
?>
up
0
phpuser
9 years ago
The algorithm from Bigtree is correct if you add some (int) cast
<?php
  
function easter_date ($Year) {
  
      
/*
       G is the Golden Number-1
       H is 23-Epact (modulo 30)
       I is the number of days from 21 March to the Paschal full moon
       J is the weekday for the Paschal full moon (0=Sunday,
         1=Monday, etc.)
       L is the number of days from 21 March to the Sunday on or before
         the Paschal full moon (a number between -6 and 28)
       */
      

        
$G = $Year % 19;
        
$C = (int)($Year / 100);
        
$H = (int)($C - (int)($C / 4) - (int)((8*$C+13) / 25) + 19*$G + 15) % 30;
        
$I = (int)$H - (int)($H / 28)*(1 - (int)($H / 28)*(int)(29 / ($H + 1))*((int)(21 - $G) / 11));
        
$J = ($Year + (int)($Year/4) + $I + 2 - $C + (int)($C/4)) % 7;
        
$L = $I - $J;
        
$m = 3 + (int)(($L + 40) / 44);
        
$d = $L + 28 - 31 * ((int)($m / 4));
        
$y = $Year;
        
$E = mktime(0,0,0, $m, $d, $y);

         return
$E;

   }
?>
up
-1
luca at musician dot org
2 years ago
Due to range limitations of core functions such as easter_date(), mktime(), strtotime(), I wrote this function to get the Easter Day in string format yyyy-mm-dd.

function myEaster($year)
{
    /*Warning: easter_date(): This function is only valid for years between 1970 and 2037
     * The easter_days() function can be used instead of easter_date() to calculate Easter for years which fall outside the range.
      */
     //The next line would do the work if there were no limitations:
    //return date("Y-m-d",easter_date($year));

    /*Outside range (1970,2037) they advise to use easter_days().
     * Unfortunately, when you have to create a date object as 21-03-yyyy to which add easter_days(), then obtain Easter,
     * functions like strtotime(), DateTime::createFromFormat() will fail. (return value is 01-01-1970)
     */
    $march21=date("$year-03-21");
    $days=easter_days($year);
    if($year<=2037)
    //The next line would do the work if strtotime() wasn't affected by same limitations. But, the if..else is required to handle all years.
        $date = date("Y-m-d",strtotime(date("Y-m-d", strtotime($march21)) . " +$days day"));
    else
    {
        if($days<=10){
            $day=str_pad(21+$days, 2, '0', STR_PAD_LEFT);
            $date=date("$year-03-$day");
        }
        else
        {
            $day=str_pad($days-10, 2, '0', STR_PAD_LEFT);
            $date=date("$year-04-$day");
        }
    }

    return $date;
}
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